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Q. Balance the following chemical equation:

[tex]\[ \text{NaOH} + \text{Al}_2\text{O}_3 \rightarrow \text{NaAlO}_2 + \text{H}_2\text{O} \][/tex]

Elements:

- Reactants:
- Products:

Note: The equation provided in the question appears to be incomplete or not fully balanced. Please balance the chemical equation and provide the number of each element on both sides.

Sagot :

Let's balance the given chemical equation step-by-step:

Chemical Equation:
[tex]\[ \text{NaOH} + \text{Al}_2\text{O}_3 \rightarrow \text{NaAlO}_2 + \text{H}_2\text{O} \][/tex]

First, we need to count the number of each type of atom on both sides of the equation to determine the coefficients that will balance the equation.

Step 1: Write down the number of atoms of each element in the reactants and the products without any coefficients.

Reactants:
- Sodium (Na): 1 (from NaOH)
- Oxygen (O): 1 (from NaOH) + 3 (from Al₂O₃) = 4
- Hydrogen (H): 1 (from NaOH)
- Aluminum (Al): 2 (from Al₂O₃)

Products:
- Sodium (Na): 1 (from NaAlO₂)
- Aluminum (Al): 1 (from NaAlO₂)
- Oxygen (O): 2 (from NaAlO₂) + 1 (from H₂O) = 3
- Hydrogen (H): 2 (from H₂O)

Step 2: Assign coefficients to balance the equation.

Starting with another element that appears in a complex molecule often helps. In this case, let's balance the aluminum (Al) atoms first.

We have 2 aluminum atoms in \( \text{Al}_2\text{O}_3 \):
[tex]\[ \text{Al}_2\text{O}_3 \][/tex]

To balance the Al in the products:
[tex]\[ 2 \times \text{NaAlO}_2 \rightarrow \text{2 NaAlO}_2 \][/tex]
Now, we have 2 aluminum atoms on both sides.

Re-assess the numbers:
Products:
- Sodium (Na): 2 (from 2 × NaAlO₂)
- Aluminum (Al): 2 (from 2 × NaAlO₂)
- Oxygen (O): 4 (from 2 × NaAlO₂)
- Hydrogen (H): 2 (from H₂O)

Next, balance Sodium (Na) atoms by making coefficients of \( \text{NaOH} \) number 2 as we require 2 sodium atoms:
[tex]\[ 2 \times \text{NaOH} \rightarrow \text{2 NaOH} \][/tex]

Reactants:
- Sodium (Na): 2 (from 2 × NaOH)
- Oxygen (O): 2 (from 2 × NaOH) + 3 (from Al₂O₃) = 5
- Hydrogen (H): 2 (from 2 × NaOH)
- Aluminum (Al): 2 (from Al₂O₃)

Finally, we balance the hydrogen (H) by ensuring that the product side equals the reactant side. We currently have 2 hydrogens in the reactants from 2 NaOH, so coefficient of \( H_2O \):
[tex]\[ H_2O \rightarrow H_2O \][/tex]

Balanced Equation:
[tex]\[ 2 \text{NaOH} + \text{Al}_2\text{O}_3 \rightarrow 2 \text{NaAlO}_2 + \text{H}_2\text{O} \][/tex]

Reassess the entire equation again:

Reactants:
- Sodium (Na): 2 (from 2 × NaOH)
- Oxygen (O): 2 (from 2 × NaOH) + 3 (from Al₂O₃) = 5
- Hydrogen (H): 2 (from 2 × NaOH)
- Aluminum (Al): 2 (from Al₂O₃)

Products:
- Sodium (Na): 2 (from 2 × NaAlO₂)
- Aluminum (Al): 2 (from 2 × NaAlO₂)
- Oxygen (O): 4 (from 2 × NaAlO₂) + 1 (from H₂O) = 5
- Hydrogen (H): 2 (from H₂O)

Therefore, the coefficients for the balanced chemical equation are:
[tex]\[ 2 \text{NaOH} + \text{Al}_2\text{O}_3 \rightarrow 2 \text{NaAlO}_2 + \text{H}_2\text{O} \][/tex]

The coefficients of the balanced equation are:
[tex]\[ 2, 1, 2, 1 \][/tex]