Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Let's balance the given chemical equation step-by-step:
Chemical Equation:
[tex]\[ \text{NaOH} + \text{Al}_2\text{O}_3 \rightarrow \text{NaAlO}_2 + \text{H}_2\text{O} \][/tex]
First, we need to count the number of each type of atom on both sides of the equation to determine the coefficients that will balance the equation.
Step 1: Write down the number of atoms of each element in the reactants and the products without any coefficients.
Reactants:
- Sodium (Na): 1 (from NaOH)
- Oxygen (O): 1 (from NaOH) + 3 (from Al₂O₃) = 4
- Hydrogen (H): 1 (from NaOH)
- Aluminum (Al): 2 (from Al₂O₃)
Products:
- Sodium (Na): 1 (from NaAlO₂)
- Aluminum (Al): 1 (from NaAlO₂)
- Oxygen (O): 2 (from NaAlO₂) + 1 (from H₂O) = 3
- Hydrogen (H): 2 (from H₂O)
Step 2: Assign coefficients to balance the equation.
Starting with another element that appears in a complex molecule often helps. In this case, let's balance the aluminum (Al) atoms first.
We have 2 aluminum atoms in \( \text{Al}_2\text{O}_3 \):
[tex]\[ \text{Al}_2\text{O}_3 \][/tex]
To balance the Al in the products:
[tex]\[ 2 \times \text{NaAlO}_2 \rightarrow \text{2 NaAlO}_2 \][/tex]
Now, we have 2 aluminum atoms on both sides.
Re-assess the numbers:
Products:
- Sodium (Na): 2 (from 2 × NaAlO₂)
- Aluminum (Al): 2 (from 2 × NaAlO₂)
- Oxygen (O): 4 (from 2 × NaAlO₂)
- Hydrogen (H): 2 (from H₂O)
Next, balance Sodium (Na) atoms by making coefficients of \( \text{NaOH} \) number 2 as we require 2 sodium atoms:
[tex]\[ 2 \times \text{NaOH} \rightarrow \text{2 NaOH} \][/tex]
Reactants:
- Sodium (Na): 2 (from 2 × NaOH)
- Oxygen (O): 2 (from 2 × NaOH) + 3 (from Al₂O₃) = 5
- Hydrogen (H): 2 (from 2 × NaOH)
- Aluminum (Al): 2 (from Al₂O₃)
Finally, we balance the hydrogen (H) by ensuring that the product side equals the reactant side. We currently have 2 hydrogens in the reactants from 2 NaOH, so coefficient of \( H_2O \):
[tex]\[ H_2O \rightarrow H_2O \][/tex]
Balanced Equation:
[tex]\[ 2 \text{NaOH} + \text{Al}_2\text{O}_3 \rightarrow 2 \text{NaAlO}_2 + \text{H}_2\text{O} \][/tex]
Reassess the entire equation again:
Reactants:
- Sodium (Na): 2 (from 2 × NaOH)
- Oxygen (O): 2 (from 2 × NaOH) + 3 (from Al₂O₃) = 5
- Hydrogen (H): 2 (from 2 × NaOH)
- Aluminum (Al): 2 (from Al₂O₃)
Products:
- Sodium (Na): 2 (from 2 × NaAlO₂)
- Aluminum (Al): 2 (from 2 × NaAlO₂)
- Oxygen (O): 4 (from 2 × NaAlO₂) + 1 (from H₂O) = 5
- Hydrogen (H): 2 (from H₂O)
Therefore, the coefficients for the balanced chemical equation are:
[tex]\[ 2 \text{NaOH} + \text{Al}_2\text{O}_3 \rightarrow 2 \text{NaAlO}_2 + \text{H}_2\text{O} \][/tex]
The coefficients of the balanced equation are:
[tex]\[ 2, 1, 2, 1 \][/tex]
Chemical Equation:
[tex]\[ \text{NaOH} + \text{Al}_2\text{O}_3 \rightarrow \text{NaAlO}_2 + \text{H}_2\text{O} \][/tex]
First, we need to count the number of each type of atom on both sides of the equation to determine the coefficients that will balance the equation.
Step 1: Write down the number of atoms of each element in the reactants and the products without any coefficients.
Reactants:
- Sodium (Na): 1 (from NaOH)
- Oxygen (O): 1 (from NaOH) + 3 (from Al₂O₃) = 4
- Hydrogen (H): 1 (from NaOH)
- Aluminum (Al): 2 (from Al₂O₃)
Products:
- Sodium (Na): 1 (from NaAlO₂)
- Aluminum (Al): 1 (from NaAlO₂)
- Oxygen (O): 2 (from NaAlO₂) + 1 (from H₂O) = 3
- Hydrogen (H): 2 (from H₂O)
Step 2: Assign coefficients to balance the equation.
Starting with another element that appears in a complex molecule often helps. In this case, let's balance the aluminum (Al) atoms first.
We have 2 aluminum atoms in \( \text{Al}_2\text{O}_3 \):
[tex]\[ \text{Al}_2\text{O}_3 \][/tex]
To balance the Al in the products:
[tex]\[ 2 \times \text{NaAlO}_2 \rightarrow \text{2 NaAlO}_2 \][/tex]
Now, we have 2 aluminum atoms on both sides.
Re-assess the numbers:
Products:
- Sodium (Na): 2 (from 2 × NaAlO₂)
- Aluminum (Al): 2 (from 2 × NaAlO₂)
- Oxygen (O): 4 (from 2 × NaAlO₂)
- Hydrogen (H): 2 (from H₂O)
Next, balance Sodium (Na) atoms by making coefficients of \( \text{NaOH} \) number 2 as we require 2 sodium atoms:
[tex]\[ 2 \times \text{NaOH} \rightarrow \text{2 NaOH} \][/tex]
Reactants:
- Sodium (Na): 2 (from 2 × NaOH)
- Oxygen (O): 2 (from 2 × NaOH) + 3 (from Al₂O₃) = 5
- Hydrogen (H): 2 (from 2 × NaOH)
- Aluminum (Al): 2 (from Al₂O₃)
Finally, we balance the hydrogen (H) by ensuring that the product side equals the reactant side. We currently have 2 hydrogens in the reactants from 2 NaOH, so coefficient of \( H_2O \):
[tex]\[ H_2O \rightarrow H_2O \][/tex]
Balanced Equation:
[tex]\[ 2 \text{NaOH} + \text{Al}_2\text{O}_3 \rightarrow 2 \text{NaAlO}_2 + \text{H}_2\text{O} \][/tex]
Reassess the entire equation again:
Reactants:
- Sodium (Na): 2 (from 2 × NaOH)
- Oxygen (O): 2 (from 2 × NaOH) + 3 (from Al₂O₃) = 5
- Hydrogen (H): 2 (from 2 × NaOH)
- Aluminum (Al): 2 (from Al₂O₃)
Products:
- Sodium (Na): 2 (from 2 × NaAlO₂)
- Aluminum (Al): 2 (from 2 × NaAlO₂)
- Oxygen (O): 4 (from 2 × NaAlO₂) + 1 (from H₂O) = 5
- Hydrogen (H): 2 (from H₂O)
Therefore, the coefficients for the balanced chemical equation are:
[tex]\[ 2 \text{NaOH} + \text{Al}_2\text{O}_3 \rightarrow 2 \text{NaAlO}_2 + \text{H}_2\text{O} \][/tex]
The coefficients of the balanced equation are:
[tex]\[ 2, 1, 2, 1 \][/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
