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Show that 100 is the sum of 10 odd natural numbers.

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GinnyAnswer
Let's demonstrate that 100 is indeed the sum of the first 10 odd natural numbers. We will go through each step systematically.

Step 1: List the first 10 odd natural numbers.
The first 10 odd natural numbers are:
[tex]\[ 1, 3, 5, 7, 9, 11, 13, 15, 17, 19 \][/tex]

Step 2: Sum these numbers.
Now, we need to add these numbers together. We proceed as follows:

[tex]\[ 1 + 3 = 4 \][/tex]
[tex]\[ 4 + 5 = 9 \][/tex]
[tex]\[ 9 + 7 = 16 \][/tex]
[tex]\[ 16 + 9 = 25 \][/tex]
[tex]\[ 25 + 11 = 36 \][/tex]
[tex]\[ 36 + 13 = 49 \][/tex]
[tex]\[ 49 + 15 = 64 \][/tex]
[tex]\[ 64 + 17 = 81 \][/tex]
[tex]\[ 81 + 19 = 100 \][/tex]

Step 3: Verify the total sum.
After adding each step, the total sum is confirmed to be 100.

Thus, we have shown that the sum of the first 10 odd natural numbers (1, 3, 5, 7, 9, 11, 13, 15, 17, 19) is indeed 100.
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