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Write these values in order, starting with the smallest. The first one has been done for you.

[tex]\[
\begin{array}{ccccc}
72\% & 0.6 & \frac{21}{25} & 0.75 & \frac{1}{2} \\
\text{A} & \text{B} & \text{C} & \text{D} & \text{E}
\end{array}
\][/tex]

E \(\square\)

\(\square\)

\(\square\)

[tex]\(\square\)[/tex]


Sagot :

Certainly! Let's proceed to order the given values from smallest to largest. The given values are:
- \( 72\% \)
- \( 0.6 \)
- \( \frac{21}{25} \)
- \( 0.75 \)
- \( \frac{1}{2} \)

Initially, we have \( \frac{1}{2} \), which is equivalent to \( 0.5 \). We have already marked this as the smallest value and labeled it with \( \text{E} \).

Next, we continue by comparing the remaining values to find the next smallest value:

1. E: \( \frac{1}{2} = 0.5 \)
2. B: \( 0.6 \) (Smaller than the rest)
3. A: \( 72\% = 0.72 \)
4. D: \( 0.75 \)
5. C: \( \frac{21}{25} = 0.84 \)

Putting them in order, the sequence starting from the smallest to the largest is:
- \( 0.5 \) (E)
- \( 0.6 \) (B)
- \( 0.72 \) (A)
- \( 0.75 \) (D)
- \( 0.84 \) (C)

Hence, the ordered values with their corresponding labels are:

E \( \frac{1}{2} \)
B \( 0.6 \)
A \( 72\% \)
D \( 0.75 \)
C \( \frac{21}{25} \)

Thus, the final ordered sequence starting with E is:
E
B
A
D
C