Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Show that the Argand’s plane variable point p subject to the condition | + 1| + | − 1| = 3 describes an ellipse. Sketch it

Sagot :

Answer:

To show that the locus of a variable point \( p \) (represented by a complex number \( z \)) subject to the condition \( |z + 1| + |z - 1| = 3 \) describes an ellipse, we can follow these steps:

1. **Understand the Condition**:

  The given condition \( |z + 1| + |z - 1| = 3 \) represents the sum of the distances from the point \( z \) to the points \( -1 \) and \( 1 \).

2. **Foci of the Ellipse**:

  Recall that the definition of an ellipse is the set of points where the sum of the distances to two fixed points (foci) is a constant. Here, the fixed points (foci) are \( -1 \) and \( 1 \) on the real axis, and the constant sum is 3.

3. **Check the Major Axis Length**:

  For an ellipse with foci at \( -1 \) and \( 1 \), the sum of the distances to the foci equals the major axis length \( 2a \). So, \( 2a = 3 \), giving \( a = 1.5 \).

4. **Determine the Distance Between the Foci**:

  The distance between the foci is \( 2c \). Since the foci are \( -1 \) and \( 1 \), the distance between them is \( 2 \), so \( c = 1 \).

5. **Find the Minor Axis Length**:

  The relationship between \( a \), \( b \) (the semi-minor axis), and \( c \) in an ellipse is given by \( c^2 = a^2 - b^2 \). Substituting the known values:

  \[

  1^2 = 1.5^2 - b^2

  \]

  \[

  1 = 2.25 - b^2

  \]

  \[

  b^2 = 2.25 - 1 = 1.25

  \]

  \[

  b = \sqrt{1.25} = \frac{\sqrt{5}}{2}

  \]

Thus, the ellipse has a semi-major axis \( a = 1.5 \) and a semi-minor axis \( b = \frac{\sqrt{5}}{2} \).

**To sketch the ellipse:**

1. Draw the real axis and mark the foci at \( -1 \) and \( 1 \).

2. Draw the major axis with a total length of 3 units, centered at the origin.

3. Draw the minor axis perpendicular to the major axis at the center, with a total length of \( \sqrt{5} \) units.

Here's a sketch of the ellipse:

```plaintext

y-axis

^

|

|           .             .  (points on the ellipse)

|        .     .

|     .           .

|    .             .

|   .               .

| .                 .

|.                   .

----------------------------- -> x-axis

-2  -1    0    1     2

```

To accurately draw this:

- The center is at the origin (0,0).

- The foci are at \((-1, 0)\) and \( (1, 0) \).

- The vertices on the major axis are at \((\pm 1.5, 0)\).

- The vertices on the minor axis are at \((0, \pm \frac{\sqrt{5}}{2})\).

This sketch represents an ellipse centered at the origin with the major axis along the x-axis and the minor axis along the y-axis.