Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Archie is the captain of a ship.
There is a whirlpool 40 km due north of the ship.
There is a volcano due east of the whirlpool, at a bearing
of 058° from the ship.
Archie wants to sail in a straight line that passes through
the point halfway between the whirlpool and
the volcano
.
What bearing should he sail
on?
Give your answer to the nearest degree.


Sagot :

Answer:

  039°

Step-by-step explanation:

You want the bearing of a point that is halfway between 40 km due north and a point due east of that on a bearing of 58°.

Tangent

The distance east of the whirlpool can be found using the tangent relation:

  Tan = Opposite/Adjacent

  tan(58°) = (east distance)/(40 km) . . . . substitute given values

  east distance = (40 km)·tan(58°)

Target

The point for which we are aiming is half this distance east of the whirlpool. The angle can be found using the same relation:

  [tex]\tan(\text{bearing})=\dfrac{\dfrac{1}{2}\cdot\text{east distance}}{40\text{ km}}=\dfrac{(40\text{ km})\tan(58^\circ)}{2\cdot(40\text{ km})}\\\\\\\text{bearing}=\arctan\left(\dfrac{\tan(58^\circ)}{2}\right)\approx 38.7^\circ[/tex]

The captain should sail on a bearing of about 39°.

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.