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### Question 4 (Multiple Choice Worth 1 Point)

[tex]$ \$[/tex] 240[tex]$ is invested at an interest rate of $[/tex]9\%$ per year and is compounded monthly. How much will the investment be worth in 14 years?

Use the compound interest formula:
[tex]\[ A = P \left( 1 + \frac{r}{n} \right)^{nt} \][/tex]

A. \$68.39
B. \$704.28
C. \$842.13
D. \$846.10

### Question 5 (Multiple Choice Worth 1 Point)

A sailboat depreciates [tex]$15\%$[/tex] each year. If the sailboat was \$9,500 at its time of purchase, what is the value of the sailboat after 7 years?

A. \$
B. \$
C. \$
D. \$

(Note: The options for Question 5 were not provided in the original text and need to be filled in accordingly.)

Sagot :

To determine how much a $240 investment is worth after 14 years with an interest rate of 9% per year compounded monthly, we need to use the compound interest formula. The compound interest formula is given by:

[tex]\[ A = P \left(1 + \frac{r}{n}\right)^{nt} \][/tex]

Where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (the initial amount of money).
- \( r \) is the annual interest rate (decimal).
- \( n \) is the number of times that interest is compounded per year.
- \( t \) is the time the money is invested for, in years.

Given:
- \( P = 240 \)
- \( r = 9\% = 0.09 \)
- \( n = 12 \) (since the interest is compounded monthly)
- \( t = 14 \) years

Now, plug these values into the compound interest formula:

[tex]\[ A = 240 \left(1 + \frac{0.09}{12}\right)^{12 \times 14} \][/tex]

First, calculate \(\frac{0.09}{12}\):

[tex]\[ \frac{0.09}{12} = 0.0075 \][/tex]

Next, add 1 to the result:

[tex]\[ 1 + 0.0075 = 1.0075 \][/tex]

Then, multiply the number of times interest is compounded per year by the number of years:

[tex]\[ 12 \times 14 = 168 \][/tex]

Raise the base to the power of this product:

[tex]\[ 1.0075^{168} \approx 3.508885595 \][/tex]

Finally, multiply this result by the principal amount to find the future value:

[tex]\[ A = 240 \times 3.508885595 \approx 842.13 \][/tex]

Therefore, the investment will be worth approximately \$842.13 in 14 years.

For the given multiple-choice options, the correct answer is:

[tex]\[ \boxed{\$842.13} \][/tex]

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Now, let's address the value of the sailboat after 7 years, given annual depreciation of 15%.

The depreciation formula used is:

[tex]\[ V = P(1 - r)^t \][/tex]

Where:
- \( V \) is the value of the sailboat after depreciation
- \( P \) is the initial value of the sailboat
- \( r \) is the annual depreciation rate (as a decimal)
- \( t \) is the time in years

Given:
- \( P = 9500 \)
- \( r = 15\% = 0.15 \)
- \( t = 7 \) years

Substitute these values into the depreciation formula:

[tex]\[ V = 9500 \times (1 - 0.15)^7 \][/tex]

First, calculate \( 1 - 0.15 \):

[tex]\[ 1 - 0.15 = 0.85 \][/tex]

Next, raise this to the 7th power:

[tex]\[ 0.85^7 \][/tex]

Calculate \( 0.85^7 \):

[tex]\[ 0.85^7 \approx 0.3119501125 \][/tex]

Finally, multiply this result by the initial value of the sailboat:

[tex]\[ V = 9500 \times 0.3119501125 \approx 2963.53 \][/tex]

Therefore, the value of the sailboat after 7 years is approximately \$2963.53.