To determine if the given relation is a function, we need to check if each input \( x \) has exactly one output \( y \). In other words, every \( x \) value in the set of ordered pairs should be paired with one and only one \( y \) value.
Let’s examine the pairs provided:
[tex]\[
\begin{array}{|c|c|}
\hline
x & y \\
\hline
1 & 4 \\
\hline
-1 & -2 \\
\hline
3 & 10 \\
\hline
5 & 16 \\
\hline
\end{array}
\][/tex]
Now, let's list the \( x \) values:
- \( x = 1 \)
- \( x = -1 \)
- \( x = 3 \)
- \( x = 5 \)
Since all \( x \) values are unique and appear only once in the table, there is no case where a single \( x \) value is mapped to more than one \( y \) value.
Thus, each \( x \) value has exactly one corresponding \( y \) value, which meets the criterion for the relation to be a function.
Therefore, the given relation is a function.
The answer is:
Yes
