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Silver owns two houses in the same community. The ratio of the values of the first house to the second house is 10:15 respectively. It is estimated that in 6years, the value of the first house will increase by $3556 and that of the second house will increase by $30,825.00. If the new ratio is 3:4, find the original value of the first house.​

Sagot :

chibabykalu16

Answer:

-$156,502.

Step-by-step explanation:

Given:

  • The ratio of the first house to the second house = 10:15

After 6 years

  • First house will increase by $3556
  • The second house increased by $30,825.00

Let the original value of the first house be 10x and the second house be 15x (based on the initial ratio).

After 6 years, the value of the first house increases by $3556, making it 10x + 3556.

The value of the second house increases by $30,825, making it 15x + 30,825.

The new ratio is 3:4, so we can set up the equation:

(10x + 3556) / (15x + 30,825) = 3/4

Note: We're dividing based on the principle of ratio that 10:15 = 10/15

Cross-multiply and simplify:

40x + 14224 = 45x + 92475

Subtract 40x from both sides:

14224 = 5x + 92475

Subtract 92475 from both sides:

-78251 = 5x

Divide by 5:

x = -15650.2

Now, the original value of the first house is 10x:

10(-15650.2) = -$156,502

The calculated original value of the first house is −$156,502. This means there might be an error in the initial assumptions or a mistake in setting up the equations.

So, the original value of the first house is -$156,502.

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