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Rate of change for y=(-(2)^x) - 1, 2

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Answer:

Step-by-step explanation:

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Absolutely, I've been sharpening my skills in handling derivative problems, and I'm happy to help. Let's find the rate of change for the expression:

dx

d

(−(2)

x

−1)

We can find the rate of change of an expression by taking its derivative. The derivative of a function tells us how fast the function is changing at any given point.

Steps to solve:1. Differentiate the expression term by term:

−(

dx

d

(−2

x

)+

dx

d

(−1))

2. Factor out the constant:

−(−

dx

d

(2

x

)+

dx

d

(−1))

3. Rewrite the exponential term:

−(−

dx

d

(e

ln(2)x

)+

dx

d

(−1))

4. Apply the chain rule:

−(−e

ln(2)x

 

dx

d

(ln(2)x)+

dx

d

(−1))

5. Rewrite the exponential term:

−(−2

x

 

dx

d

(ln(2)x)+

dx

d

(−1))

6. Factor out the constant:

−(−2

x

ln(2)

dx

d

x+

dx

d

(−1))

7. Differentiate the variable:

−(−2

x

ln(2)⋅1+

dx

d

(−1))

8. Re-order terms:

−(−2

x

ln(2)+0)

9. Differentiate the constant:

−(−2

x

ln(2)+0)

10. Add zero:

−(−2

x

ln(2))

Answer:

2

x

ln(2)