Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Answer:
Step-by-step explanation:
Gemini has just been updated. See update
close
Conversation with Gemini
edit
Rate of change for y=(-(2)^x) - 1, 2
Show drafts
expand_more
volume_up
Absolutely, I've been sharpening my skills in handling derivative problems, and I'm happy to help. Let's find the rate of change for the expression:
−
dx
d
(−(2)
x
−1)
We can find the rate of change of an expression by taking its derivative. The derivative of a function tells us how fast the function is changing at any given point.
Steps to solve:1. Differentiate the expression term by term:
−(
dx
d
(−2
x
)+
dx
d
(−1))
2. Factor out the constant:
−(−
dx
d
(2
x
)+
dx
d
(−1))
3. Rewrite the exponential term:
−(−
dx
d
(e
ln(2)x
)+
dx
d
(−1))
4. Apply the chain rule:
−(−e
ln(2)x
dx
d
(ln(2)x)+
dx
d
(−1))
5. Rewrite the exponential term:
−(−2
x
dx
d
(ln(2)x)+
dx
d
(−1))
6. Factor out the constant:
−(−2
x
ln(2)
dx
d
x+
dx
d
(−1))
7. Differentiate the variable:
−(−2
x
ln(2)⋅1+
dx
d
(−1))
8. Re-order terms:
−(−2
x
ln(2)+0)
9. Differentiate the constant:
−(−2
x
ln(2)+0)
10. Add zero:
−(−2
x
ln(2))
Answer:
2
x
ln(2)
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
