Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

If [tex]\( h(x) = 3x + 5 \)[/tex], find the values of [tex]\( x \)[/tex] for which [tex]\( h(x) \ \textgreater \ 17 \)[/tex].

Sagot :

GinnyAnswer
Sure! Let's solve the inequality to find the values of \( x \) for which \( h(x) > 17 \), where \( h(x) = 3x + 5 \).

1. Start with the inequality:
[tex]\[ 3x + 5 > 17 \][/tex]

2. To isolate the term with \( x \), subtract 5 from both sides of the inequality:
[tex]\[ 3x + 5 - 5 > 17 - 5 \][/tex]
Simplifying this gives:
[tex]\[ 3x > 12 \][/tex]

3. Now, to solve for \( x \), divide both sides of the inequality by 3:
[tex]\[ \frac{3x}{3} > \frac{12}{3} \][/tex]
Simplifying this gives:
[tex]\[ x > 4 \][/tex]

Therefore, the values of [tex]\( x \)[/tex] for which [tex]\( h(x) > 17 \)[/tex] are [tex]\( x > 4 \)[/tex].
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.