Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
To determine the standard cell notation for a galvanic cell made with zinc (Zn) and gold (Au), let's follow these steps:
1. Identify the half-reactions:
- Oxidation (anode reaction): This is where the metal loses electrons (is oxidized).
- Zinc (Zn) is more reactive than gold (Au), meaning zinc will be the one that gets oxidized.
- The oxidation half-reaction for zinc is: \( \text{Zn(s)} \rightarrow \text{Zn}^{2+}(\text{aq}) + 2e^- \)
- Reduction (cathode reaction): This is where the ions gain electrons (are reduced).
- Gold ions will be reduced because zinc is oxidized.
- The reduction half-reaction for gold ions is: \( \text{Au}^+(\text{aq}) + e^- \rightarrow \text{Au(s)} \)
2. Construct the cell notation:
Standard cell notation is written as:
\( \text{Anode (s)} | \text{Anode ion (aq)} || \text{Cathode ion (aq)} | \text{Cathode (s)} \)
- From the oxidation half-reaction, the anode is zinc and the notation for the anode part is: \( \text{Zn(s)} | \text{Zn}^{2+}(\text{aq}) \)
- From the reduction half-reaction, the cathode is gold and the notation for the cathode part is: \( \text{Au}^+(\text{aq}) | \text{Au(s)} \)
3. Combine the parts:
Using the standard form, combine the anode and cathode parts of the cell notation:
[tex]\[ \text{Zn(s)} | \text{Zn}^{2+}(\text{aq}) || \text{Au}^+(\text{aq}) | \text{Au(s)} \][/tex]
By carefully combining these components, we find the correct standard cell notation.
Given the options:
A. \( \text{Au}^+(\text{aq}) | \text{Au(s)} || \text{Zn(s)} | \text{Zn}^{2+}(\text{aq}) \)
B. \( \text{Zn(s)} | \text{Zn}^{2+}(\text{aq}) || \text{Au}^+(\text{aq}) | \text{Au(s)} \)
C. \( \text{Zn}^{2+}(\text{aq}) | \text{Zn(s)} || \text{Au(s)} | \text{Au}^+(\text{aq}) \)
D. \( \text{Au(s)} | \text{Au}^+(\text{aq}) || \text{Zn}^{2+}(\text{aq}) | \text{Zn(s)} \)
The correct notation is:
B. \( \text{Zn(s)} | \text{Zn}^{2+}(\text{aq}) || \text{Au}^+(\text{aq}) | \text{Au(s)} \)
Therefore, the answer is B.
1. Identify the half-reactions:
- Oxidation (anode reaction): This is where the metal loses electrons (is oxidized).
- Zinc (Zn) is more reactive than gold (Au), meaning zinc will be the one that gets oxidized.
- The oxidation half-reaction for zinc is: \( \text{Zn(s)} \rightarrow \text{Zn}^{2+}(\text{aq}) + 2e^- \)
- Reduction (cathode reaction): This is where the ions gain electrons (are reduced).
- Gold ions will be reduced because zinc is oxidized.
- The reduction half-reaction for gold ions is: \( \text{Au}^+(\text{aq}) + e^- \rightarrow \text{Au(s)} \)
2. Construct the cell notation:
Standard cell notation is written as:
\( \text{Anode (s)} | \text{Anode ion (aq)} || \text{Cathode ion (aq)} | \text{Cathode (s)} \)
- From the oxidation half-reaction, the anode is zinc and the notation for the anode part is: \( \text{Zn(s)} | \text{Zn}^{2+}(\text{aq}) \)
- From the reduction half-reaction, the cathode is gold and the notation for the cathode part is: \( \text{Au}^+(\text{aq}) | \text{Au(s)} \)
3. Combine the parts:
Using the standard form, combine the anode and cathode parts of the cell notation:
[tex]\[ \text{Zn(s)} | \text{Zn}^{2+}(\text{aq}) || \text{Au}^+(\text{aq}) | \text{Au(s)} \][/tex]
By carefully combining these components, we find the correct standard cell notation.
Given the options:
A. \( \text{Au}^+(\text{aq}) | \text{Au(s)} || \text{Zn(s)} | \text{Zn}^{2+}(\text{aq}) \)
B. \( \text{Zn(s)} | \text{Zn}^{2+}(\text{aq}) || \text{Au}^+(\text{aq}) | \text{Au(s)} \)
C. \( \text{Zn}^{2+}(\text{aq}) | \text{Zn(s)} || \text{Au(s)} | \text{Au}^+(\text{aq}) \)
D. \( \text{Au(s)} | \text{Au}^+(\text{aq}) || \text{Zn}^{2+}(\text{aq}) | \text{Zn(s)} \)
The correct notation is:
B. \( \text{Zn(s)} | \text{Zn}^{2+}(\text{aq}) || \text{Au}^+(\text{aq}) | \text{Au(s)} \)
Therefore, the answer is B.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.