Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To determine how many grams of NaCl would be produced from 507 grams of FeCl₂, let's go through the problem step-by-step.
### Step 1: Determine the molar masses
First, we need to calculate the molar masses of the compounds involved.
- For FeCl₂:
- The atomic mass of Fe (iron) is approximately 55.845 g/mol.
- The atomic mass of Cl (chlorine) is approximately 35.453 g/mol.
- Therefore, the molar mass of FeCl₂ is:
[tex]\[ \text{Molar mass of FeCl}_2 = 55.845 + 2 \times 35.453 = 126.751 \, \text{g/mol} \][/tex]
- For NaCl:
- The atomic mass of Na (sodium) is approximately 22.99 g/mol.
- The atomic mass of Cl (chlorine) is approximately 35.453 g/mol.
- Thus, the molar mass of NaCl is:
[tex]\[ \text{Molar mass of NaCl} = 22.99 + 35.453 = 58.443 \, \text{g/mol} \][/tex]
### Step 2: Calculate the moles of FeCl₂
We have 507 grams of FeCl₂. To determine the number of moles of FeCl₂, use the formula:
[tex]\[ \text{moles of FeCl}_2 = \frac{\text{mass}}{\text{molar mass}} \][/tex]
[tex]\[ \text{moles of FeCl}_2 = \frac{507 \, \text{g}}{126.751 \, \text{g/mol}} \approx 3.999968 \, \text{moles} \][/tex]
### Step 3: Use stoichiometry to find moles of NaCl produced
According to the balanced chemical equation:
[tex]\[ FeCl_2 + 2NaOH \rightarrow Fe(OH)_2(s) + 2NaCl \][/tex]
1 mole of FeCl₂ produces 2 moles of NaCl. Therefore, the moles of NaCl produced will be:
[tex]\[ \text{moles of NaCl} = 2 \times \text{moles of FeCl}_2 = 2 \times 3.999968 = 7.999936 \, \text{moles} \][/tex]
### Step 4: Calculate the mass of NaCl produced
Finally, convert the moles of NaCl to grams using its molar mass:
[tex]\[ \text{mass of NaCl} = \text{moles of NaCl} \times \text{molar mass of NaCl} \][/tex]
[tex]\[ \text{mass of NaCl} = 7.999936 \, \text{moles} \times 58.443 \, \text{g/mol} \approx 467.52 \, \text{g} \][/tex]
### Conclusion
The mass of NaCl produced from 507 grams of FeCl₂ is approximately 467.52 grams. Therefore, the correct answer is:
B. [tex]\(467.52 \, \text{g} \)[/tex] NaCl
### Step 1: Determine the molar masses
First, we need to calculate the molar masses of the compounds involved.
- For FeCl₂:
- The atomic mass of Fe (iron) is approximately 55.845 g/mol.
- The atomic mass of Cl (chlorine) is approximately 35.453 g/mol.
- Therefore, the molar mass of FeCl₂ is:
[tex]\[ \text{Molar mass of FeCl}_2 = 55.845 + 2 \times 35.453 = 126.751 \, \text{g/mol} \][/tex]
- For NaCl:
- The atomic mass of Na (sodium) is approximately 22.99 g/mol.
- The atomic mass of Cl (chlorine) is approximately 35.453 g/mol.
- Thus, the molar mass of NaCl is:
[tex]\[ \text{Molar mass of NaCl} = 22.99 + 35.453 = 58.443 \, \text{g/mol} \][/tex]
### Step 2: Calculate the moles of FeCl₂
We have 507 grams of FeCl₂. To determine the number of moles of FeCl₂, use the formula:
[tex]\[ \text{moles of FeCl}_2 = \frac{\text{mass}}{\text{molar mass}} \][/tex]
[tex]\[ \text{moles of FeCl}_2 = \frac{507 \, \text{g}}{126.751 \, \text{g/mol}} \approx 3.999968 \, \text{moles} \][/tex]
### Step 3: Use stoichiometry to find moles of NaCl produced
According to the balanced chemical equation:
[tex]\[ FeCl_2 + 2NaOH \rightarrow Fe(OH)_2(s) + 2NaCl \][/tex]
1 mole of FeCl₂ produces 2 moles of NaCl. Therefore, the moles of NaCl produced will be:
[tex]\[ \text{moles of NaCl} = 2 \times \text{moles of FeCl}_2 = 2 \times 3.999968 = 7.999936 \, \text{moles} \][/tex]
### Step 4: Calculate the mass of NaCl produced
Finally, convert the moles of NaCl to grams using its molar mass:
[tex]\[ \text{mass of NaCl} = \text{moles of NaCl} \times \text{molar mass of NaCl} \][/tex]
[tex]\[ \text{mass of NaCl} = 7.999936 \, \text{moles} \times 58.443 \, \text{g/mol} \approx 467.52 \, \text{g} \][/tex]
### Conclusion
The mass of NaCl produced from 507 grams of FeCl₂ is approximately 467.52 grams. Therefore, the correct answer is:
B. [tex]\(467.52 \, \text{g} \)[/tex] NaCl
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.