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Given the linear function [tex]$f(x)=-4x+12[tex]$[/tex], determine the location of the [tex]$[/tex]x$[/tex]-intercept.

A. [tex]$(-3, 0)$[/tex]
B. [tex]$(0, 12)$[/tex]
C. [tex]$(3, 0)$[/tex]
D. [tex]$(0, 3)$[/tex]


Sagot :

To determine the location of the \( x \)-intercept for the linear function \( f(x) = -4x + 12 \), we need to find the value of \( x \) where the function intersects the \( x \)-axis. This occurs when \( f(x) = 0 \), because on the \( x \)-axis, the \( y \)-coordinate is zero.

Here is the step-by-step process to find the \( x \)-intercept:

1. Start with the given function and set it equal to 0:
[tex]\[ f(x) = -4x + 12 \][/tex]
[tex]\[ 0 = -4x + 12 \][/tex]

2. Solve the equation for \( x \):
[tex]\[ 0 = -4x + 12 \][/tex]

3. Add \( 4x \) to both sides to isolate the term containing \( x \):
[tex]\[ 4x = 12 \][/tex]

4. Divide both sides by 4 to solve for \( x \):
[tex]\[ x = \frac{12}{4} \][/tex]
[tex]\[ x = 3 \][/tex]

Therefore, the \( x \)-intercept of the function \( f(x) = -4x + 12 \) is at the point \((3, 0)\).

So, the correct choice is:
[tex]\[ (3, 0) \][/tex]
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