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The functions \( f \) and \( g \) are defined as \( f(x) = x - 1 \) and \( g(x) = \sqrt{x + 3} \).

a) Find the domain of \( f \), \( g \), \( f + g \), \( f - g \), \( f g \), \( f \circ f \), \( \frac{f}{g} \), and \( \frac{g}{f} \).

b) Find \( (f + g)(x) \), \( (f - g)(x) \), \( (fg)(x) \), \( (f \circ f)(x) \), \( \left(\frac{f}{g}\right)(x) \), and \( \left(\frac{g}{f}\right)(x) \).

a) The domain of \( f \) is \(\square\)
(Type your answer in interval notation.)

Sagot :

Let's go through the problem step by step.

### Part a)
Finding the domains of each function and their combinations:

1. Domain of \( f(x) = x - 1 \):
This function is a linear function and is defined for all real numbers.
[tex]\[ \text{Domain of } f = (-\infty, \infty) \][/tex]

2. Domain of \( g(x) = \sqrt{x+3} \):
The square root function is defined when the expression inside the square root is non-negative.
[tex]\[ x + 3 \geq 0 \Rightarrow x \geq -3 \][/tex]
[tex]\[ \text{Domain of } g = [-3, \infty) \][/tex]

3. Domain of \( (f+g)(x) \):
The domain of \( f+g \) is the intersection of the domains of \( f \) and \( g \).
[tex]\[ \text{Domain of } (f+g) = (-\infty, \infty) \cap [-3, \infty) = [-3, \infty) \][/tex]

4. Domain of \( (f-g)(x) \):
Similar to \( f+g \), the domain of \( f-g \) is also the intersection of the domains of \( f \) and \( g \).
[tex]\[ \text{Domain of } (f-g) = [-3, \infty) \][/tex]

5. Domain of \( (fg)(x) \):
The domain of \( f \cdot g \) is again the intersection of the domains of \( f \) and \( g \).
[tex]\[ \text{Domain of } (fg) = [-3, \infty) \][/tex]

6. Domain of \( ff(x) = f(f(x)) \):
We first find the domain of the inner function \( f(x) \) which is \( (-\infty, \infty) \). Since \( f \) is \( x-1 \), applying \( f \) again results in \( f(f(x)) = f(x-1) = (x-1) - 1 = x - 2 \). The function \( x-2 \) is also defined for all real numbers.
[tex]\[ \text{Domain of } ff = (-\infty, \infty) \][/tex]

7. Domain of \( \frac{f}{g}(x) \):
The function \( g(x) \) must not be zero to avoid division by zero. Since \( g(x) = \sqrt{x+3} \), \( g(x) = 0 \) at \( x = -3 \).
[tex]\[ x \neq -3 \][/tex]
So, the domain is:
[tex]\[ \text{Domain of } \frac{f}{g} = [-3, \infty) \setminus \{-3\} \][/tex]

8. Domain of \( \frac{g}{f}(x) \):
The function \( f(x) \) must not be zero to avoid division by zero. Since \( f(x) = x - 1 \), \( f(x) = 0 \) at \( x = 1 \).
[tex]\[ x \neq 1 \][/tex]
So, the domain is:
[tex]\[ \text{Domain of } \frac{g}{f} = [-3, \infty) \setminus \{1\} \][/tex]

### Part b)
Finding the expressions for combined functions:

1. \( (f+g)(x) \):
[tex]\[ (f+g)(x) = f(x) + g(x) = (x-1) + \sqrt{x+3} \][/tex]
[tex]\[ (f+g)(x) = x - 1 + \sqrt{x+3} \][/tex]

2. \( (f-g)(x) \):
[tex]\[ (f-g)(x) = f(x) - g(x) = (x-1) - \sqrt{x+3} \][/tex]
[tex]\[ (f-g)(x) = x - 1 - \sqrt{x+3} \][/tex]

3. \( (fg)(x) \):
[tex]\[ (fg)(x) = f(x) \cdot g(x) = (x-1) \cdot \sqrt{x+3} \][/tex]
[tex]\[ (fg)(x) = (x-1) \sqrt{x+3} \][/tex]

4. \( ff(x) \):
[tex]\[ ff(x) = f(f(x)) = f(x-1) = (x-1) - 1 \][/tex]
[tex]\[ ff(x) = x - 2 \][/tex]

5. \( \left( \frac{f}{g} \right)(x) \):
[tex]\[ \left( \frac{f}{g} \right)(x) = \frac{f(x)}{g(x)} = \frac{x-1}{\sqrt{x+3}} \][/tex]

6. \( \left( \frac{g}{f} \right)(x) \):
[tex]\[ \left( \frac{g}{f} \right)(x) = \frac{g(x)}{f(x)} = \frac{\sqrt{x+3}}{x-1} \][/tex]

### Summary of Part a)

- Domain of \( f \): \((-∞, ∞)\)
- Domain of \( g \): \([-3, ∞)\)
- Domain of \( (f+g) \): \([-3, ∞)\)
- Domain of \( (f-g) \): \([-3, ∞)\)
- Domain of \( (fg) \): \([-3, ∞)\)
- Domain of \( ff \): \((-∞, ∞)\)
- Domain of \( \frac{f}{g} \): \([-3, ∞) \setminus \{-3\}\)
- Domain of [tex]\( \frac{g}{f} \)[/tex]: [tex]\([-3, ∞) \setminus \{1\}\)[/tex]