Answered

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If [tex]$f(x) = x^3 - 2x - 1[tex]$[/tex], then [tex]$[/tex]f(-2) =$[/tex]

Sagot :

GinnyAnswer
To solve for \( f(-2) \) when \( f(x) = x^3 - 2x - 1 \):

1. Start with the given function:
[tex]\[ f(x) = x^3 - 2x - 1 \][/tex]

2. Substitute \( x = -2 \) into the function:
[tex]\[ f(-2) = (-2)^3 - 2(-2) - 1 \][/tex]

3. Calculate each term individually:
- First term: \((-2)^3\)
[tex]\[ (-2)^3 = -8 \][/tex]

- Second term: \(-2(-2)\)
[tex]\[ -2(-2) = 4 \][/tex]

- Third term: \(-1\) remains \(-1\)

4. Combine these results:
[tex]\[ f(-2) = -8 + 4 - 1 \][/tex]

5. Perform the addition and subtraction:
[tex]\[ -8 + 4 = -4 \][/tex]
[tex]\[ -4 - 1 = -5 \][/tex]

Therefore, [tex]\( f(-2) = -5 \)[/tex].
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