Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
To determine when the toy rocket will reach its maximum height, we need to focus on the function for the height of the rocket:
[tex]\[ h(t) = -16t^2 + 200t + 50 \][/tex]
This function is a quadratic equation of the form \( h(t) = at^2 + bt + c \), where:
- \( a = -16 \)
- \( b = 200 \)
- \( c = 50 \)
For a parabolic function opening downwards (as indicated by the negative coefficient of \( t^2 \)), the maximum height occurs at the vertex of the parabola. The time \( t \) at which this maximum height occurs can be determined by using the vertex formula for a quadratic equation, which is given by:
[tex]\[ t = -\frac{b}{2a} \][/tex]
Substituting the values of \( a \) and \( b \) into the formula, we get:
[tex]\[ t = -\frac{200}{2 \cdot -16} \][/tex]
Calculating the above, we have:
[tex]\[ t = -\frac{200}{-32} \][/tex]
[tex]\[ t = \frac{200}{32} \][/tex]
[tex]\[ t = 6.25 \][/tex]
Therefore, the toy rocket will reach its maximum height at \( t = 6.25 \) seconds.
The correct answer is:
6.25 seconds
[tex]\[ h(t) = -16t^2 + 200t + 50 \][/tex]
This function is a quadratic equation of the form \( h(t) = at^2 + bt + c \), where:
- \( a = -16 \)
- \( b = 200 \)
- \( c = 50 \)
For a parabolic function opening downwards (as indicated by the negative coefficient of \( t^2 \)), the maximum height occurs at the vertex of the parabola. The time \( t \) at which this maximum height occurs can be determined by using the vertex formula for a quadratic equation, which is given by:
[tex]\[ t = -\frac{b}{2a} \][/tex]
Substituting the values of \( a \) and \( b \) into the formula, we get:
[tex]\[ t = -\frac{200}{2 \cdot -16} \][/tex]
Calculating the above, we have:
[tex]\[ t = -\frac{200}{-32} \][/tex]
[tex]\[ t = \frac{200}{32} \][/tex]
[tex]\[ t = 6.25 \][/tex]
Therefore, the toy rocket will reach its maximum height at \( t = 6.25 \) seconds.
The correct answer is:
6.25 seconds
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.