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What is the equation of the line parallel to the given line with an [tex]x[/tex]-intercept of 4?

[tex]
y = \square x + \square
[/tex]


Sagot :

To determine the equation of a line parallel to a given line that has an \( x \)-intercept of 4, we need to follow these steps:

1. Equation of the original line:
The original line is provided in the standard form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.

2. Parallel line characteristics:
Parallel lines have the same slope (\( m \)). Therefore, the new line will have the same slope as the original line.

3. Determining the new line's intercept:
For our new line with an \( x \)-intercept of 4, by definition, the \( x \)-intercept is the point where the line crosses the x-axis (\( y = 0 \)). Hence, if we substitute \( x = 4 \) into the line's equation, we should get \( y = 0 \).

4. Finding the y-intercept (b):
Let's generalize the equation of the new line as \( y = mx + b \). Since we know it intercepts the x-axis at \( x = 4 \):
[tex]\[ 0 = m \cdot 4 + b \][/tex]
Solving for \( b \):
[tex]\[ 0 = 4m + b \implies b = -4m \][/tex]

Now, substituting \( b = -4m \) back into the line equation \( y = mx + b \), we get:
[tex]\[ y = mx - 4m \][/tex]

However, when we rewrite the final equation, the standard way to express a line equation is simplified based on the given information. If our aim is to find \( x \)- and \( y \)-coordinates where \( y = 0 \):

The final simplified form of any line parallel to the original line with an \( x \)-intercept of 4 will point to \( y = 0 \).

The resulting equation based on these steps is:
[tex]\[ y = 0 \][/tex]