At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
To find the probability of 5 cars waiting in line, we need to follow these steps:
1. Calculate the total frequency of all cars:
The given data shows the number of cars waiting at the bank and their respective frequencies over a 60-minute period.
[tex]\[ \text{Total frequency} = 2 + 9 + 16 + 12 + 8 + 6 + 4 + 2 + 1 \][/tex]
2. Identify the frequency of 5 cars waiting:
From the table, the frequency of 5 cars waiting is 6.
3. Calculate the probability:
The probability of an event is the ratio of the frequency of the event to the total frequency of all events.
[tex]\[ P(5 \text{ cars}) = \frac{\text{Frequency of 5 cars}}{\text{Total frequency}} \][/tex]
4. Substitute the values:
Using the calculated total frequency and the given frequency:
[tex]\[ \text{Total frequency} = 60 \][/tex]
[tex]\[ \text{Frequency of 5 cars} = 6 \][/tex]
[tex]\[ P(5 \text{ cars}) = \frac{6}{60} \][/tex]
5. Simplify the fraction:
[tex]\[ P(5 \text{ cars}) = \frac{6}{60} = 0.1 \][/tex]
Thus, the probability of 5 cars waiting in line is
[tex]\[ P(5) = 0.1 \][/tex]
1. Calculate the total frequency of all cars:
The given data shows the number of cars waiting at the bank and their respective frequencies over a 60-minute period.
[tex]\[ \text{Total frequency} = 2 + 9 + 16 + 12 + 8 + 6 + 4 + 2 + 1 \][/tex]
2. Identify the frequency of 5 cars waiting:
From the table, the frequency of 5 cars waiting is 6.
3. Calculate the probability:
The probability of an event is the ratio of the frequency of the event to the total frequency of all events.
[tex]\[ P(5 \text{ cars}) = \frac{\text{Frequency of 5 cars}}{\text{Total frequency}} \][/tex]
4. Substitute the values:
Using the calculated total frequency and the given frequency:
[tex]\[ \text{Total frequency} = 60 \][/tex]
[tex]\[ \text{Frequency of 5 cars} = 6 \][/tex]
[tex]\[ P(5 \text{ cars}) = \frac{6}{60} \][/tex]
5. Simplify the fraction:
[tex]\[ P(5 \text{ cars}) = \frac{6}{60} = 0.1 \][/tex]
Thus, the probability of 5 cars waiting in line is
[tex]\[ P(5) = 0.1 \][/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.