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Multiply the rational expressions.

[tex]\[ \frac{p^9 q}{p^2 + p - 12} \cdot \frac{2p^2 - 11p + 15}{pq^9} = \][/tex]

[tex]\[ \square \][/tex]


Sagot :

To multiply the given rational expressions:

[tex]\[ \frac{p^9 q}{p^2 + p - 12} \cdot \frac{2p^2 - 11p + 15}{p q^9} \][/tex]

we follow these steps:

1. Factor the denominators and numerators where possible.

- For the denominator \( p^2 + p - 12 \):
[tex]\[ p^2 + p - 12 = (p + 4)(p - 3) \][/tex]

- For the numerator \( 2p^2 - 11p + 15 \):
[tex]\[ 2p^2 - 11p + 15 = (2p - 5)(p - 3) \][/tex]

Now the expressions look as follows:
[tex]\[ \frac{p^9 q}{(p + 4)(p - 3)} \cdot \frac{(2p - 5)(p - 3)}{p q^9} \][/tex]

2. Combine the two fractions into one:

[tex]\[ \frac{p^9 q \cdot (2p - 5)(p - 3)}{(p + 4)(p - 3) \cdot p q^9} \][/tex]

3. Cancel out common factors in the numerator and the denominator:

- The factor \(p - 3\) appears in both the numerator and the denominator and can be canceled out.
- The \(p\) term in the numerator and denominator can be partially canceled. Specifically, \(p^9\) in the numerator and \(p\) in the denominator leave \(p^{9-1} = p^8\).
- The \(q\) term in the numerator and denominator can be partially canceled. Specifically, \(q\) in the numerator and \(q^9\) in the denominator leave \(q^{9-1} = q^8\).

Simplifying:
[tex]\[ \frac{p^8 \cdot (2p - 5)}{(p + 4) \cdot q^8} \][/tex]

4. Write the simplified form.

The result is:
[tex]\[ \frac{p^8 (2p - 5)}{(p + 4) q^8} \][/tex]

Therefore, the simplified form of the product of the given rational expressions is:

[tex]\[ \boxed{\frac{p^8 (2p - 5)}{(p + 4) q^8}} \][/tex]