Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
¡Claro! Vamos a resolver cada parte de la pregunta paso a paso.
5) Restar los siguientes polinomios:
Dados los polinomios
[tex]\[ P(x) = x^4 - x^3 - x^2 + 2x + 2 \][/tex]
y
[tex]\[ Q(x) = 2x^2 + 3x^3 + 4x^4 - 5x + 5 \][/tex]
Resta los dos polinomios:
[tex]\[ R(x) = P(x) - Q(x) \][/tex]
[tex]\[ R(x) = (x^4 - x^3 - x^2 + 2x + 2) - (2x^2 + 3x^3 + 4x^4 - 5x + 5) \][/tex]
[tex]\[ R(x) = x^4 - x^3 - x^2 + 2x + 2 - 2x^2 - 3x^3 - 4x^4 + 5x - 5 \][/tex]
Reorganizando términos:
[tex]\[ R(x) = x^4 - 4x^4 - x^3 - 3x^3 - x^2 - 2x^2 + 2x + 5x + 2 - 5 \][/tex]
[tex]\[ R(x) = -3x^4 - 4x^3 - 3x^2 + 7x - 3 \][/tex]
6) Calcular el valor numérico de \(P(x)\) para los siguientes valores:
Dado el polinomio
[tex]\[ P(x) = \frac{x}{2} - 3x + 4x^2 - 5x^3 - \frac{2x^4}{3} + \frac{5}{4} \][/tex]
Evaluamos para cada valor de \(x\):
a) \( x = 1 \)
[tex]\[ P(1) = \frac{1}{2} - 3(1) + 4(1^2) - 5(1^3) - \frac{2(1^4)}{3} + \frac{5}{4} = -2.91666666666667 \][/tex]
b) \( x = -1 \)
[tex]\[ P(-1) = \frac{-1}{2} - 3(-1) + 4(-1)^2 - 5(-1)^3 - \frac{2(-1^4)}{3} + \frac{5}{4} = 12.0833333333333 \][/tex]
c) \( x = \frac{2}{3} \)
[tex]\[ P\left(\frac{2}{3}\right) = \frac{\frac{2}{3}}{2} - 3\left(\frac{2}{3}\right) + 4\left(\frac{2}{3}\right)^2 - 5\left(\frac{2}{3}\right)^3 - \frac{2\left(\frac{2}{3}\right)^4}{3} + \frac{5}{4} = -0.252057613168724 \][/tex]
d) \( x = -3 \)
[tex]\[ P(-3) = \frac{-3}{2} - 3(-3) + 4(-3)^2 - 5(-3)^3 - \frac{2(-3)^4}{3} + \frac{5}{4} = 125.750000000000 \][/tex]
7) Dados los polinomios:
[tex]\[ P(x) = 4x^2 - x + 2 \][/tex]
[tex]\[ Q(x) = x^3 + x - 1 \][/tex]
[tex]\[ R(x) = 2x - 1 \][/tex]
Hallar:
a) \(P(x) + Q(x)\)
[tex]\[ (4x^2 - x + 2) + (x^3 + x - 1) = x^3 + 4x^2 + 1\][/tex]
b) \(P(x) + R(x)\)
[tex]\[ (4x^2 - x + 2) + (2x - 1) = 4x^2 + x + 1 \][/tex]
c) \(Q(x) \cdot R(x)\)
[tex]\[ (x^3 + x - 1) \cdot (2x - 1) = (2x - 1)(x^3 + x - 1) \][/tex]
d) \(P(x) \cdot Q(x)\)
[tex]\[ (4x^2 - x + 2) \cdot (x^3 + x - 1) = (4x^2 - x + 2)(x^3 + x - 1) \][/tex]
e) \(P(x) / R(x)\)
[tex]\[ \frac{4x^2 - x + 2}{2x - 1} = 2x + \frac{1}{2} + \text{residuo } \frac{5}{2} \][/tex]
f) \(Q(x) / R(x)\)
[tex]\[ \frac{x^3 + x - 1}{2x - 1} = \frac{x^2}{2} + \frac{x}{4} + \frac{5}{8} + \text{residuo } \frac{-3}{8} \][/tex]
g) El resto de la división de \(P(x)\) por \(x - 1\)
[tex]\[ \frac{4x^2 - x + 2}{x - 1} \rightarrow \text{residuo} = 5 \][/tex]
h) \(P(-1)\)
[tex]\[ P(-1) = 4(-1)^2 - (-1) + 2 = 7 \][/tex]
i) \(P(-2) + [Q(-2)]^2\)
[tex]\[ P(-2) = 4(-2)^2 - (-2) + 2 = 22 \][/tex]
[tex]\[ Q(-2) = (-2)^3 + (-2) - 1 = -11 \][/tex]
[tex]\[ P(-2) + [Q(-2)]^2 = 22 + (-11)^2 = 141 \][/tex]
5) Restar los siguientes polinomios:
Dados los polinomios
[tex]\[ P(x) = x^4 - x^3 - x^2 + 2x + 2 \][/tex]
y
[tex]\[ Q(x) = 2x^2 + 3x^3 + 4x^4 - 5x + 5 \][/tex]
Resta los dos polinomios:
[tex]\[ R(x) = P(x) - Q(x) \][/tex]
[tex]\[ R(x) = (x^4 - x^3 - x^2 + 2x + 2) - (2x^2 + 3x^3 + 4x^4 - 5x + 5) \][/tex]
[tex]\[ R(x) = x^4 - x^3 - x^2 + 2x + 2 - 2x^2 - 3x^3 - 4x^4 + 5x - 5 \][/tex]
Reorganizando términos:
[tex]\[ R(x) = x^4 - 4x^4 - x^3 - 3x^3 - x^2 - 2x^2 + 2x + 5x + 2 - 5 \][/tex]
[tex]\[ R(x) = -3x^4 - 4x^3 - 3x^2 + 7x - 3 \][/tex]
6) Calcular el valor numérico de \(P(x)\) para los siguientes valores:
Dado el polinomio
[tex]\[ P(x) = \frac{x}{2} - 3x + 4x^2 - 5x^3 - \frac{2x^4}{3} + \frac{5}{4} \][/tex]
Evaluamos para cada valor de \(x\):
a) \( x = 1 \)
[tex]\[ P(1) = \frac{1}{2} - 3(1) + 4(1^2) - 5(1^3) - \frac{2(1^4)}{3} + \frac{5}{4} = -2.91666666666667 \][/tex]
b) \( x = -1 \)
[tex]\[ P(-1) = \frac{-1}{2} - 3(-1) + 4(-1)^2 - 5(-1)^3 - \frac{2(-1^4)}{3} + \frac{5}{4} = 12.0833333333333 \][/tex]
c) \( x = \frac{2}{3} \)
[tex]\[ P\left(\frac{2}{3}\right) = \frac{\frac{2}{3}}{2} - 3\left(\frac{2}{3}\right) + 4\left(\frac{2}{3}\right)^2 - 5\left(\frac{2}{3}\right)^3 - \frac{2\left(\frac{2}{3}\right)^4}{3} + \frac{5}{4} = -0.252057613168724 \][/tex]
d) \( x = -3 \)
[tex]\[ P(-3) = \frac{-3}{2} - 3(-3) + 4(-3)^2 - 5(-3)^3 - \frac{2(-3)^4}{3} + \frac{5}{4} = 125.750000000000 \][/tex]
7) Dados los polinomios:
[tex]\[ P(x) = 4x^2 - x + 2 \][/tex]
[tex]\[ Q(x) = x^3 + x - 1 \][/tex]
[tex]\[ R(x) = 2x - 1 \][/tex]
Hallar:
a) \(P(x) + Q(x)\)
[tex]\[ (4x^2 - x + 2) + (x^3 + x - 1) = x^3 + 4x^2 + 1\][/tex]
b) \(P(x) + R(x)\)
[tex]\[ (4x^2 - x + 2) + (2x - 1) = 4x^2 + x + 1 \][/tex]
c) \(Q(x) \cdot R(x)\)
[tex]\[ (x^3 + x - 1) \cdot (2x - 1) = (2x - 1)(x^3 + x - 1) \][/tex]
d) \(P(x) \cdot Q(x)\)
[tex]\[ (4x^2 - x + 2) \cdot (x^3 + x - 1) = (4x^2 - x + 2)(x^3 + x - 1) \][/tex]
e) \(P(x) / R(x)\)
[tex]\[ \frac{4x^2 - x + 2}{2x - 1} = 2x + \frac{1}{2} + \text{residuo } \frac{5}{2} \][/tex]
f) \(Q(x) / R(x)\)
[tex]\[ \frac{x^3 + x - 1}{2x - 1} = \frac{x^2}{2} + \frac{x}{4} + \frac{5}{8} + \text{residuo } \frac{-3}{8} \][/tex]
g) El resto de la división de \(P(x)\) por \(x - 1\)
[tex]\[ \frac{4x^2 - x + 2}{x - 1} \rightarrow \text{residuo} = 5 \][/tex]
h) \(P(-1)\)
[tex]\[ P(-1) = 4(-1)^2 - (-1) + 2 = 7 \][/tex]
i) \(P(-2) + [Q(-2)]^2\)
[tex]\[ P(-2) = 4(-2)^2 - (-2) + 2 = 22 \][/tex]
[tex]\[ Q(-2) = (-2)^3 + (-2) - 1 = -11 \][/tex]
[tex]\[ P(-2) + [Q(-2)]^2 = 22 + (-11)^2 = 141 \][/tex]
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.