Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Certainly! Let's walk through the process of determining whether the given reaction is endothermic or exothermic, and calculating the enthalpy of reaction.
### Given Information:
1. The enthalpy of formation (\(\Delta H_f\)) of \(C_6H_6(l)\) is \(49.0 \, \text{kJ/mol}\).
2. The reaction is:
[tex]\[ 6 \, C \text{ (s, graphite)} + 3 \, H_2 \text{ (g)} \rightarrow C_6H_6 \text{ (l)} \][/tex]
### Step-by-Step Solution:
1. Enthalpy of Formation for Reactants:
- The enthalpy of formation (\(\Delta H_f\)) for elements in their standard state (like graphite carbon and hydrogen gas) is zero.
- Therefore, for the reactants \(6 \, C \text{ (s, graphite)}\) and \(3 \, H_2 \text{ (g)}\):
[tex]\[ \sum(\Delta H_{f, \text{reactants}}) = 0 \, \text{kJ/mol} \][/tex]
2. Enthalpy of Formation for the Product:
- Given the enthalpy of formation for \(C_6H_6(l)\) is:
[tex]\[ \Delta H_{f, \text{product}} = 49.0 \, \text{kJ/mol} \][/tex]
3. Calculate the Enthalpy of Reaction:
Using the formula for the enthalpy of reaction:
[tex]\[ \Delta H_{\text{rxn}} = \sum \left( \Delta H_{f, \text{products}} \right) - \sum \left( \Delta H_{f, \text{reactants}} \right) \][/tex]
We substitute the values:
[tex]\[ \Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol} - 0 \, \text{kJ/mol} = 49.0 \, \text{kJ/mol} \][/tex]
4. Determine if the Reaction is Endothermic or Exothermic:
- A reaction is endothermic if it absorbs energy from the surroundings (i.e., \(\Delta H_{\text{rxn}} > 0\)).
- A reaction is exothermic if it releases energy to the surroundings (i.e., \(\Delta H_{\text{rxn}} < 0\)).
Since \(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\) is positive, the reaction is endothermic.
### Conclusion:
The reaction is endothermic with an enthalpy of reaction \(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\).
- Answer: Endothermic; \(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\).
Hence, the correct selection from the given options is:
endothermic; [tex]\(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\)[/tex].
### Given Information:
1. The enthalpy of formation (\(\Delta H_f\)) of \(C_6H_6(l)\) is \(49.0 \, \text{kJ/mol}\).
2. The reaction is:
[tex]\[ 6 \, C \text{ (s, graphite)} + 3 \, H_2 \text{ (g)} \rightarrow C_6H_6 \text{ (l)} \][/tex]
### Step-by-Step Solution:
1. Enthalpy of Formation for Reactants:
- The enthalpy of formation (\(\Delta H_f\)) for elements in their standard state (like graphite carbon and hydrogen gas) is zero.
- Therefore, for the reactants \(6 \, C \text{ (s, graphite)}\) and \(3 \, H_2 \text{ (g)}\):
[tex]\[ \sum(\Delta H_{f, \text{reactants}}) = 0 \, \text{kJ/mol} \][/tex]
2. Enthalpy of Formation for the Product:
- Given the enthalpy of formation for \(C_6H_6(l)\) is:
[tex]\[ \Delta H_{f, \text{product}} = 49.0 \, \text{kJ/mol} \][/tex]
3. Calculate the Enthalpy of Reaction:
Using the formula for the enthalpy of reaction:
[tex]\[ \Delta H_{\text{rxn}} = \sum \left( \Delta H_{f, \text{products}} \right) - \sum \left( \Delta H_{f, \text{reactants}} \right) \][/tex]
We substitute the values:
[tex]\[ \Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol} - 0 \, \text{kJ/mol} = 49.0 \, \text{kJ/mol} \][/tex]
4. Determine if the Reaction is Endothermic or Exothermic:
- A reaction is endothermic if it absorbs energy from the surroundings (i.e., \(\Delta H_{\text{rxn}} > 0\)).
- A reaction is exothermic if it releases energy to the surroundings (i.e., \(\Delta H_{\text{rxn}} < 0\)).
Since \(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\) is positive, the reaction is endothermic.
### Conclusion:
The reaction is endothermic with an enthalpy of reaction \(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\).
- Answer: Endothermic; \(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\).
Hence, the correct selection from the given options is:
endothermic; [tex]\(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\)[/tex].
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.