Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Certainly! Let's walk through the process of determining whether the given reaction is endothermic or exothermic, and calculating the enthalpy of reaction.
### Given Information:
1. The enthalpy of formation (\(\Delta H_f\)) of \(C_6H_6(l)\) is \(49.0 \, \text{kJ/mol}\).
2. The reaction is:
[tex]\[ 6 \, C \text{ (s, graphite)} + 3 \, H_2 \text{ (g)} \rightarrow C_6H_6 \text{ (l)} \][/tex]
### Step-by-Step Solution:
1. Enthalpy of Formation for Reactants:
- The enthalpy of formation (\(\Delta H_f\)) for elements in their standard state (like graphite carbon and hydrogen gas) is zero.
- Therefore, for the reactants \(6 \, C \text{ (s, graphite)}\) and \(3 \, H_2 \text{ (g)}\):
[tex]\[ \sum(\Delta H_{f, \text{reactants}}) = 0 \, \text{kJ/mol} \][/tex]
2. Enthalpy of Formation for the Product:
- Given the enthalpy of formation for \(C_6H_6(l)\) is:
[tex]\[ \Delta H_{f, \text{product}} = 49.0 \, \text{kJ/mol} \][/tex]
3. Calculate the Enthalpy of Reaction:
Using the formula for the enthalpy of reaction:
[tex]\[ \Delta H_{\text{rxn}} = \sum \left( \Delta H_{f, \text{products}} \right) - \sum \left( \Delta H_{f, \text{reactants}} \right) \][/tex]
We substitute the values:
[tex]\[ \Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol} - 0 \, \text{kJ/mol} = 49.0 \, \text{kJ/mol} \][/tex]
4. Determine if the Reaction is Endothermic or Exothermic:
- A reaction is endothermic if it absorbs energy from the surroundings (i.e., \(\Delta H_{\text{rxn}} > 0\)).
- A reaction is exothermic if it releases energy to the surroundings (i.e., \(\Delta H_{\text{rxn}} < 0\)).
Since \(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\) is positive, the reaction is endothermic.
### Conclusion:
The reaction is endothermic with an enthalpy of reaction \(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\).
- Answer: Endothermic; \(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\).
Hence, the correct selection from the given options is:
endothermic; [tex]\(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\)[/tex].
### Given Information:
1. The enthalpy of formation (\(\Delta H_f\)) of \(C_6H_6(l)\) is \(49.0 \, \text{kJ/mol}\).
2. The reaction is:
[tex]\[ 6 \, C \text{ (s, graphite)} + 3 \, H_2 \text{ (g)} \rightarrow C_6H_6 \text{ (l)} \][/tex]
### Step-by-Step Solution:
1. Enthalpy of Formation for Reactants:
- The enthalpy of formation (\(\Delta H_f\)) for elements in their standard state (like graphite carbon and hydrogen gas) is zero.
- Therefore, for the reactants \(6 \, C \text{ (s, graphite)}\) and \(3 \, H_2 \text{ (g)}\):
[tex]\[ \sum(\Delta H_{f, \text{reactants}}) = 0 \, \text{kJ/mol} \][/tex]
2. Enthalpy of Formation for the Product:
- Given the enthalpy of formation for \(C_6H_6(l)\) is:
[tex]\[ \Delta H_{f, \text{product}} = 49.0 \, \text{kJ/mol} \][/tex]
3. Calculate the Enthalpy of Reaction:
Using the formula for the enthalpy of reaction:
[tex]\[ \Delta H_{\text{rxn}} = \sum \left( \Delta H_{f, \text{products}} \right) - \sum \left( \Delta H_{f, \text{reactants}} \right) \][/tex]
We substitute the values:
[tex]\[ \Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol} - 0 \, \text{kJ/mol} = 49.0 \, \text{kJ/mol} \][/tex]
4. Determine if the Reaction is Endothermic or Exothermic:
- A reaction is endothermic if it absorbs energy from the surroundings (i.e., \(\Delta H_{\text{rxn}} > 0\)).
- A reaction is exothermic if it releases energy to the surroundings (i.e., \(\Delta H_{\text{rxn}} < 0\)).
Since \(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\) is positive, the reaction is endothermic.
### Conclusion:
The reaction is endothermic with an enthalpy of reaction \(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\).
- Answer: Endothermic; \(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\).
Hence, the correct selection from the given options is:
endothermic; [tex]\(\Delta H_{\text{rxn}} = 49.0 \, \text{kJ/mol}\)[/tex].
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.