Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Absolutely! To find a function rule that matches the given table of values, we start by noting the pairs of \((x, y)\) values:
[tex]\[ \begin{align*} (3, 13), \\ (5, 31), \\ (7, 57), \\ (9, 91). \end{align*} \][/tex]
We aim to find a polynomial function of the form:
[tex]\[ y = ax^2 + bx + c \][/tex]
We will determine the coefficients \(a\), \(b\), and \(c\).
### Step-by-Step Solution
1. Set up a system of equations:
For each pair \((x, y)\), substitute the values into the polynomial equation:
[tex]\[ \begin{align*} 13 &= a(3)^2 + b(3) + c, \\ 31 &= a(5)^2 + b(5) + c, \\ 57 &= a(7)^2 + b(7) + c, \\ 91 &= a(9)^2 + b(9) + c. \end{align*} \][/tex]
2. Expand and simplify:
[tex]\[ \begin{align*} 13 &= 9a + 3b + c, \\ 31 &= 25a + 5b + c, \\ 57 &= 49a + 7b + c, \\ 91 &= 81a + 9b + c. \end{align*} \][/tex]
3. Solve the system of equations:
Solving the above system, we find:
[tex]\[ a = 1, \quad b = 1, \quad c = 1 \][/tex]
### Final Function Rule
From the coefficients obtained, the polynomial function that matches the given table of values is:
[tex]\[ y = x^2 + x + 1 \][/tex]
### Verification
Let's verify by substituting each value of \(x\) back into the function:
1. For \(x = 3\):
[tex]\[ y = 3^2 + 3 + 1 = 9 + 3 + 1 = 13 \][/tex]
2. For \(x = 5\):
[tex]\[ y = 5^2 + 5 + 1 = 25 + 5 + 1 = 31 \][/tex]
3. For \(x = 7\):
[tex]\[ y = 7^2 + 7 + 1 = 49 + 7 + 1 = 57 \][/tex]
4. For \(x = 9\):
[tex]\[ y = 9^2 + 9 + 1 = 81 + 9 + 1 = 91 \][/tex]
Therefore, the function rule [tex]\(y = x^2 + x + 1\)[/tex] correctly matches the given table of values.
[tex]\[ \begin{align*} (3, 13), \\ (5, 31), \\ (7, 57), \\ (9, 91). \end{align*} \][/tex]
We aim to find a polynomial function of the form:
[tex]\[ y = ax^2 + bx + c \][/tex]
We will determine the coefficients \(a\), \(b\), and \(c\).
### Step-by-Step Solution
1. Set up a system of equations:
For each pair \((x, y)\), substitute the values into the polynomial equation:
[tex]\[ \begin{align*} 13 &= a(3)^2 + b(3) + c, \\ 31 &= a(5)^2 + b(5) + c, \\ 57 &= a(7)^2 + b(7) + c, \\ 91 &= a(9)^2 + b(9) + c. \end{align*} \][/tex]
2. Expand and simplify:
[tex]\[ \begin{align*} 13 &= 9a + 3b + c, \\ 31 &= 25a + 5b + c, \\ 57 &= 49a + 7b + c, \\ 91 &= 81a + 9b + c. \end{align*} \][/tex]
3. Solve the system of equations:
Solving the above system, we find:
[tex]\[ a = 1, \quad b = 1, \quad c = 1 \][/tex]
### Final Function Rule
From the coefficients obtained, the polynomial function that matches the given table of values is:
[tex]\[ y = x^2 + x + 1 \][/tex]
### Verification
Let's verify by substituting each value of \(x\) back into the function:
1. For \(x = 3\):
[tex]\[ y = 3^2 + 3 + 1 = 9 + 3 + 1 = 13 \][/tex]
2. For \(x = 5\):
[tex]\[ y = 5^2 + 5 + 1 = 25 + 5 + 1 = 31 \][/tex]
3. For \(x = 7\):
[tex]\[ y = 7^2 + 7 + 1 = 49 + 7 + 1 = 57 \][/tex]
4. For \(x = 9\):
[tex]\[ y = 9^2 + 9 + 1 = 81 + 9 + 1 = 91 \][/tex]
Therefore, the function rule [tex]\(y = x^2 + x + 1\)[/tex] correctly matches the given table of values.
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.