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If [tex]$a=6-\sqrt{35}[tex]$[/tex], find the value of [tex]$[/tex]a+\frac{1}{a}$[/tex].

Sagot :

Sure! Let's solve the problem step-by-step. The given expression is \( a = 6 - \sqrt{35} \) and we need to find the value of \( a + \frac{1}{a} \).

1. Value of \( a \):
The value of \( a \) is directly given:
[tex]\[ a = 6 - \sqrt{35} \][/tex]

2. Calculate \( \frac{1}{a} \):
To find \( \frac{1}{a} \), we need to take the reciprocal of \( a \):
[tex]\[ \frac{1}{a} = \frac{1}{6 - \sqrt{35}} \][/tex]
Preparing it further, without losing the general meaning, it simplifies to:
[tex]\[ \frac{1}{a} = 11.916079783099628 \][/tex]

3. Add \( a \) and \( \frac{1}{a} \):
Now, we add the value of \( a \) and the value of \( \frac{1}{a} \):
[tex]\[ a + \frac{1}{a} = 0.08392021690038387 + 11.916079783099628 \][/tex]

4. Final Result:
Adding these two values together, we get:
[tex]\[ a + \frac{1}{a} = 12.00000000000001 \][/tex]

Therefore, the value of \( a + \frac{1}{a} \) is
[tex]\[ \boxed{12.00000000000001} \][/tex]