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The given line passes through the points \((-4,-3)\) and \((4,1)\).

What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point \((-4,3)\)?

A. \( y - 3 = -2(x + 4) \)

B. \( y - 3 = -\frac{1}{2}(x + 4) \)

C. \( y - 3 = \frac{1}{2}(x + 4) \)

D. [tex]\( y - 3 = 2(x + 4) \)[/tex]


Sagot :

Certainly! Let's find the equation of the line that is perpendicular to the given line and passes through the point \((-4, 3)\).

### Step-by-Step Solution

1. Identify the given points and find the slope of the given line:

The given points are \((-4, -3)\) and \((4, 1)\).

2. Calculate the slope of the given line:

The slope \(m_1\) of a line passing through two points \((x_1, y_1)\) and \((x_2, y_2)\) is calculated using the formula:
[tex]\[ m_1 = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
Substituting the coordinates:
[tex]\[ m_1 = \frac{1 - (-3)}{4 - (-4)} = \frac{1 + 3}{4 + 4} = \frac{4}{8} = \frac{1}{2} \][/tex]

3. Find the slope of the line perpendicular to the given line:

The slope \(m_2\) of the line perpendicular to the given line is the negative reciprocal of \(m_1\):
[tex]\[ m_2 = -\frac{1}{m_1} = -\frac{1}{\frac{1}{2}} = -2 \][/tex]

4. Use the point-slope form to write the equation of the perpendicular line:

The point-slope form of the equation of a line is:
[tex]\[ y - y_1 = m(x - x_1) \][/tex]
Here, the point is \((-4, 3)\) and the slope \(m_2 = -2\). Substituting these values into the point-slope form:
[tex]\[ y - 3 = -2(x + 4) \][/tex]

### Conclusion

The equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point \((-4, 3)\) is:
[tex]\[ y - 3 = -2(x + 4) \][/tex]

Thus, the correct multiple-choice answer is:
[tex]$[tex]$\boxed{y - 3 = -2(x + 4)}$[/tex]$[/tex]