Answered

Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

A cannon ball is launched into the air with an upward velocity of 391 feet per second, from a 3-foot tall cannon. The height of the cannon ball after seconds can be found using the equation h(t)=16t^2+391t+3 Approximately how long will it take for the cannon ball to be 619 feet high? Round answers to the nearest tenth if necessary. units: How long long will it take to hit the ground? units:

Sagot :

Luv2Teach

Answer:

Step-by-step explanation:

Your position equation is given as

[tex]h(t)=-16t^2+391t+3[/tex]

If you would like to find the time(s) that the object is 619 feet high, we have to fill in h(t) with 619 and do the algebra:

[tex]619=-16t^2+391t+3\\0=-16t^2+391t-616[/tex]  and then factor. It's easiest to use the quadratic formula for this. The 2 times are t = 1.7 s, 22.7 s

If we want to know how long the object is in the air, set h(t) equal to 0 and factor. Again, use the quadratic formula and the time is 24.4 s

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.