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What is the value of [tex]$x[tex]$[/tex] in the following logarithmic function: [tex]$[/tex]\log_2(32) = x$[/tex]?

A. 6
B. 5
C. 4
D. 3


Sagot :

To find the value of \( x \) in the logarithmic equation \( \log_2(32) = x \), we can use the properties of logarithms and exponents.

1. Understanding the logarithmic equation:
[tex]\[ \log_2(32) = x \][/tex]
This equation means: "To what power must 2 be raised, to obtain 32?"

2. Rewriting the equation in exponential form:
[tex]\[ 2^x = 32 \][/tex]

3. Recognizing powers of 2:
To solve this, identify that \( 32 \) is a power of 2. Specifically,
[tex]\[ 32 = 2^5 \][/tex]

4. Matching the exponents:
Given that \( 2^x = 32 \) and also \( 32 = 2^5 \), we can see that:
[tex]\[ 2^x = 2^5 \][/tex]

5. Equating the exponents:
Since the bases are the same, we can set the exponents equal to each other:
[tex]\[ x = 5 \][/tex]

Therefore, the value of [tex]\( x \)[/tex] that satisfies the equation [tex]\( \log_2(32) = x \)[/tex] is [tex]\( \boxed{5} \)[/tex].