Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Given the problem, let's break down the solution step-by-step:
1. Volume of the Column:
- The total volume of the column of crackers is given as 15 cubic inches.
2. Number of Crackers:
- There are 40 crackers in the column.
3. Volume of Each Cracker:
- To find the volume of each cracker, divide the total volume of the column by the number of crackers:
[tex]\[ \text{Volume of each cracker} = \frac{\text{Total volume of column}}{\text{Number of crackers}} = \frac{15 \text{ in}^3}{40} = 0.375 \text{ cubic inches} \][/tex]
4. Dimensions of Each Cracker:
- The length of each cracker is 2 inches, and the width is \(1 \frac{1}{2}\) inches.
[tex]\[ \text{Length} = 2 \text{ inches}, \quad \text{Width} = 1.5 \text{ inches} \][/tex]
5. Height of Each Cracker:
- The volume of a rectangular prism (or cracker in this case) is calculated as:
[tex]\[ \text{Volume} = \text{Length} \times \text{Width} \times \text{Height} \][/tex]
- Given that the volume of each cracker is 0.375 cubic inches, we can solve for the height \( h \):
[tex]\[ 0.375 = 2 \times 1.5 \times h \][/tex]
- Simplify the equation:
[tex]\[ 0.375 = 3 \times h \][/tex]
- Solve for \( h \):
[tex]\[ h = \frac{0.375}{3} = 0.125 \text{ inches} \][/tex]
6. Conclusion:
- The height of each cracker is 0.125 inches.
Thus, from the given multiple-choice options, the correct answer is:
[tex]\[ \frac{1}{8} \text{ inch} \][/tex]
Therefore, the height of each individual cracker is [tex]\( \frac{1}{8} \)[/tex] inch.
1. Volume of the Column:
- The total volume of the column of crackers is given as 15 cubic inches.
2. Number of Crackers:
- There are 40 crackers in the column.
3. Volume of Each Cracker:
- To find the volume of each cracker, divide the total volume of the column by the number of crackers:
[tex]\[ \text{Volume of each cracker} = \frac{\text{Total volume of column}}{\text{Number of crackers}} = \frac{15 \text{ in}^3}{40} = 0.375 \text{ cubic inches} \][/tex]
4. Dimensions of Each Cracker:
- The length of each cracker is 2 inches, and the width is \(1 \frac{1}{2}\) inches.
[tex]\[ \text{Length} = 2 \text{ inches}, \quad \text{Width} = 1.5 \text{ inches} \][/tex]
5. Height of Each Cracker:
- The volume of a rectangular prism (or cracker in this case) is calculated as:
[tex]\[ \text{Volume} = \text{Length} \times \text{Width} \times \text{Height} \][/tex]
- Given that the volume of each cracker is 0.375 cubic inches, we can solve for the height \( h \):
[tex]\[ 0.375 = 2 \times 1.5 \times h \][/tex]
- Simplify the equation:
[tex]\[ 0.375 = 3 \times h \][/tex]
- Solve for \( h \):
[tex]\[ h = \frac{0.375}{3} = 0.125 \text{ inches} \][/tex]
6. Conclusion:
- The height of each cracker is 0.125 inches.
Thus, from the given multiple-choice options, the correct answer is:
[tex]\[ \frac{1}{8} \text{ inch} \][/tex]
Therefore, the height of each individual cracker is [tex]\( \frac{1}{8} \)[/tex] inch.
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.