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Given:
[tex]\[ q_{H_2O} + q_{cal} = 2020 \, \text{J} \][/tex]
[tex]\[ q_{\text{unknown}} = -2020 \, \text{J} \][/tex]

The thermal energy comes from a \( 50.0 \, \text{g} \) sample of unknown metal. The metal cools from \( 225^{\circ} \text{C} \) to \( 19.3^{\circ} \text{C} \).

What is the specific heat capacity of the material?

Sagot :

To determine the specific heat capacity of the unknown metal, follow these steps:

1. Determine the change in temperature \(\Delta T\):
- Initial temperature (\( T_{\text{initial}} \)) = \( 225.0^\circ C \)
- Final temperature (\( T_{\text{final}} \)) = \( 19.3^\circ C \)
- \(\Delta T = T_{\text{initial}} - T_{\text{final}} = 225.0^\circ C - 19.3^\circ C\)
- \(\Delta T = 205.7^\circ C\)

2. Identify the given values:
- Thermal energy (\( q \)) = 2020 J
- Mass (\( m \)) = 50.0 g

3. Recall the formula for specific heat capacity (c):
[tex]\[ q = m \cdot c \cdot \Delta T \][/tex]
In this formula, \( q \) is the thermal energy absorbed or released, \( m \) is the mass of the substance, \( c \) is the specific heat capacity, and \( \Delta T \) is the change in temperature.

4. Rearrange the formula to solve for the specific heat capacity (c):
[tex]\[ c = \frac{q}{m \cdot \Delta T} \][/tex]

5. Plug in the known values into the rearranged formula:
[tex]\[ c = \frac{2020 \, \text{J}}{50.0 \, \text{g} \cdot 205.7^\circ C} \][/tex]

6. Calculate the specific heat capacity (c):
[tex]\[ c = \frac{2020}{50.0 \times 205.7} \][/tex]
[tex]\[ c \approx 0.1964 \, \text{J/(g} \cdot \text{°C)} \][/tex]

Thus, the specific heat capacity of the unknown metal is approximately [tex]\( 0.1964 \, \text{J/(g} \cdot \text{°C)} \)[/tex].
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