madey21
Answered

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Given the reaction:

[tex]\[ 2 HCl + Mg \rightarrow MgCl_2 + H_2 \][/tex]

If 0.486 g of Mg was the limiting reactant for the system, how many moles of Mg were used in the reaction?


Sagot :

To determine the number of moles of magnesium (Mg) used in the reaction, follow these steps:

1. Identify the given information:
- Mass of magnesium (\( Mg \)) used: \( 0.486 \) grams.

2. Find the molar mass of magnesium:
- The molar mass of magnesium (\( Mg \)) is given as \( 24.305 \) grams per mole (g/mol).

3. Calculate the number of moles of magnesium:
- To find the moles of magnesium, use the formula:
[tex]\[ \text{moles of Mg} = \frac{\text{mass of Mg}}{\text{molar mass of Mg}} \][/tex]

4. Substitute the given values:
- Mass of magnesium: \( 0.486 \) grams.
- Molar mass of magnesium: \( 24.305 \) grams per mole.

5. Perform the calculation:
[tex]\[ \text{moles of Mg} = \frac{0.486 \text{ grams}}{24.305 \text{ grams per mole}} \][/tex]

6. Get the result:
- Upon performing the division, you find:
[tex]\[ \text{moles of Mg} \approx 0.019995885620242747 \][/tex]

So, the number of moles of [tex]\( Mg \)[/tex] that were used in the reaction is approximately [tex]\( 0.019995885620242747 \)[/tex] moles.
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