To determine the mole ratio of hydrogen to water in the reaction \(2 \text{H}_2 + \text{O}_2 \rightarrow 2 \text{H}_2\text{O}\), let's follow these steps:
1. Identify the coefficients in the balanced chemical equation:
[tex]\[ 2 \text{H}_2 + \text{O}_2 \rightarrow 2 \text{H}_2\text{O} \][/tex]
The coefficient of hydrogen (\(\text{H}_2\)) is 2, and the coefficient of water (\(\text{H}_2\text{O}\)) is also 2.
2. Write the mole ratio using these coefficients:
The mole ratio of hydrogen to water can be written directly from these coefficients. That is:
[tex]\[ \frac{2 \text{ moles H}_2}{2 \text{ moles H}_2\text{O}} \][/tex]
3. Simplify the ratio:
[tex]\[ \frac{2}{2} = 1 \][/tex]
Therefore, the simplified mole ratio of hydrogen to water is 1:1.
Given the choices:
- F \(2:2\)
- G \(2:1\)
- H \(1:2\)
- ] \(4:4\)
The correct option is F [tex]\(2:2\)[/tex]. However, in terms of a simplified ratio, it is 1:1, but among the given choices, [tex]\(2:2\)[/tex] is the closest representation. Therefore, the correct answer is [tex]\(2:2\)[/tex].
