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Solve the following:

1. \(\left(1.20 \times 10^4\right) \times \left(2.152 \times 10^2\right) = \square \times 10^6\)

2. [tex]\(\frac{208}{5.3} = \square\)[/tex]


Sagot :

To solve the given problem, we'll break it down into two parts.

### Part 1: Multiplication and Scientific Notation
First, we want to compute the product of two numbers expressed in scientific notation:

[tex]\[ (1.20 \times 10^4) \times (2.152 \times 10^2) \][/tex]

1. Multiply the coefficients:
[tex]\[ 1.20 \times 2.152 = 2.5824 \][/tex]

2. Add the exponents:
[tex]\[ 10^4 \times 10^2 = 10^{4+2} = 10^6 \][/tex]

Thus, the product can be expressed as:
[tex]\[ (1.20 \times 10^4) \times (2.152 \times 10^2) = 2.5824 \times 10^6 \][/tex]

To check the original multiplication without considering scientific notation:
1. [tex]\[ 1.20 \times 10^4 = 12000 \][/tex]
2. [tex]\[ 2.152 \times 10^2 = 215.2 \][/tex]
3. [tex]\[ 12000 \times 215.2 = 2582400.0 \][/tex]

Therefore:
[tex]\[ 2582400.0 = 2.5824 \times 10^6 \][/tex]

We find that \( C = 2.5824 \).

### Part 2: Division
Second, we need to calculate the division:

[tex]\[ \frac{208}{5.3} \][/tex]

Perform the division:
[tex]\[ \frac{208}{5.3} \approx 39.24528301886792 \][/tex]

Thus, the steps give the final answers:
1. \((1.20 \times 10^4) \times (2.152 \times 10^2) = 2.5824 \times 10^6\)
2. \(\frac{208}{5.3} \approx 39.24528301886792\)

Conclusively, filling in the squares, we get:

[tex]\[ \begin{array}{l} (1.20 \times 10^4) \times (2.152 \times 10^2) = 2.5824 \times 10^6 \\ \frac{208}{5.3} = 39.24528301886792 \end{array} \][/tex]