Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Sure, let's go through this step-by-step to determine the relationships between the lines \(PQ\) and \(RS\) in both cases.
### Case (a): \(P(1,2,3)\), \(Q(4,5,6)\), \(R(-2,3,5)\), \(S(4,9,11)\)
1. Calculate Direction Vectors:
- For line \(PQ\):
[tex]\[ \vec{PQ} = Q - P = (4-1, 5-2, 6-3) = (3, 3, 3) \][/tex]
- For line \(RS\):
[tex]\[ \vec{RS} = S - R = (4-(-2), 9-3, 11-5) = (6, 6, 6) \][/tex]
2. Cross Product:
To check if the vectors are parallel, we compute the cross product:
[tex]\[ \vec{PQ} \times \vec{RS} = \left| \begin{matrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 3 & 3 & 3 \\ 6 & 6 & 6 \end{matrix} \right| = (0, 0, 0) \][/tex]
Since the cross product is zero, the direction vectors are parallel.
3. Dot Product:
To check if they are perpendicular, we compute the dot product:
[tex]\[ \vec{PQ} \cdot \vec{RS} = 3 \cdot 6 + 3 \cdot 6 + 3 \cdot 6 = 18 + 18 + 18 = 54 \][/tex]
The dot product is not zero, so the vectors are not perpendicular.
Conclusion for Case (a): The lines \(PQ\) and \(RS\) are parallel.
### Case (b): \(P(3,-1,-3)\), \(Q(2,-3,1)\), \(R(3,-2,5)\), \(S(-1,-2,1)\)
1. Calculate Direction Vectors:
- For line \(PQ\):
[tex]\[ \vec{PQ} = Q - P = (2-3, -3-(-1), 1-(-3)) = (-1, -2, 4) \][/tex]
- For line \(RS\):
[tex]\[ \vec{RS} = S - R = (-1-3, -2-(-2), 1-5) = (-4, 0, -4) \][/tex]
2. Cross Product:
To check if the vectors are parallel, we compute the cross product:
[tex]\[ \vec{PQ} \times \vec{RS} = \left| \begin{matrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ -1 & -2 & 4 \\ -4 & 0 & -4 \end{matrix} \right| = (8, -20, -8) \][/tex]
Since the cross product is not zero, the direction vectors are not parallel.
3. Dot Product:
To check if they are perpendicular, we compute the dot product:
[tex]\[ \vec{PQ} \cdot \vec{RS} = (-1) \cdot (-4) + (-2) \cdot 0 + 4 \cdot (-4) = 4 + 0 - 16 = -12 \][/tex]
The dot product is not zero, so the vectors are not perpendicular.
Conclusion for Case (b): The lines \(PQ\) and \(RS\) intersect.
### Summary:
- Case (a): The lines \(PQ\) and \(RS\) are parallel.
- Case (b): The lines [tex]\(PQ\)[/tex] and [tex]\(RS\)[/tex] intersect but are not perpendicular.
### Case (a): \(P(1,2,3)\), \(Q(4,5,6)\), \(R(-2,3,5)\), \(S(4,9,11)\)
1. Calculate Direction Vectors:
- For line \(PQ\):
[tex]\[ \vec{PQ} = Q - P = (4-1, 5-2, 6-3) = (3, 3, 3) \][/tex]
- For line \(RS\):
[tex]\[ \vec{RS} = S - R = (4-(-2), 9-3, 11-5) = (6, 6, 6) \][/tex]
2. Cross Product:
To check if the vectors are parallel, we compute the cross product:
[tex]\[ \vec{PQ} \times \vec{RS} = \left| \begin{matrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 3 & 3 & 3 \\ 6 & 6 & 6 \end{matrix} \right| = (0, 0, 0) \][/tex]
Since the cross product is zero, the direction vectors are parallel.
3. Dot Product:
To check if they are perpendicular, we compute the dot product:
[tex]\[ \vec{PQ} \cdot \vec{RS} = 3 \cdot 6 + 3 \cdot 6 + 3 \cdot 6 = 18 + 18 + 18 = 54 \][/tex]
The dot product is not zero, so the vectors are not perpendicular.
Conclusion for Case (a): The lines \(PQ\) and \(RS\) are parallel.
### Case (b): \(P(3,-1,-3)\), \(Q(2,-3,1)\), \(R(3,-2,5)\), \(S(-1,-2,1)\)
1. Calculate Direction Vectors:
- For line \(PQ\):
[tex]\[ \vec{PQ} = Q - P = (2-3, -3-(-1), 1-(-3)) = (-1, -2, 4) \][/tex]
- For line \(RS\):
[tex]\[ \vec{RS} = S - R = (-1-3, -2-(-2), 1-5) = (-4, 0, -4) \][/tex]
2. Cross Product:
To check if the vectors are parallel, we compute the cross product:
[tex]\[ \vec{PQ} \times \vec{RS} = \left| \begin{matrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ -1 & -2 & 4 \\ -4 & 0 & -4 \end{matrix} \right| = (8, -20, -8) \][/tex]
Since the cross product is not zero, the direction vectors are not parallel.
3. Dot Product:
To check if they are perpendicular, we compute the dot product:
[tex]\[ \vec{PQ} \cdot \vec{RS} = (-1) \cdot (-4) + (-2) \cdot 0 + 4 \cdot (-4) = 4 + 0 - 16 = -12 \][/tex]
The dot product is not zero, so the vectors are not perpendicular.
Conclusion for Case (b): The lines \(PQ\) and \(RS\) intersect.
### Summary:
- Case (a): The lines \(PQ\) and \(RS\) are parallel.
- Case (b): The lines [tex]\(PQ\)[/tex] and [tex]\(RS\)[/tex] intersect but are not perpendicular.
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.