Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

What is the molecule shown below
A. 2,3-dimethylhexane
B. 2-pentylpropane
C. 4-propylpentane
D. Octane

What Is The Molecule Shown Below A 23dimethylhexane B 2pentylpropane C 4propylpentane D Octane class=

Sagot :

Answer:

A. 2,3-dimethylhexane

Explanation:

To determine what is the molecule shown, you need to: identify radical groups and count the carbons.

  • Identify radical groups: Radical groups are groups of atoms that act as a single unit, such as Hydroxyl ([tex]OH^-[/tex]) and Methyl ([tex]CH_3^+[/tex]), and those atoms are highly reactive, having unpaired electrons.
  • Count the carbons: We count the carbons in a way that we can get as many carbons as possible, so the first carbon we count is the far left carbon, and we count in a straight line 6 carbons.

The numbers at the beginning of the name point where the methyl groups are located, so in the second and third carbon from left to right (therefore, 2,3), and since we have two, it is dimethyl. The term "hexane" is the number of carbons that compose the very core of the molecule.

In the image below, the molecule of 2,3-dimethylhexane is mirrored, but as you can see, there is methyl on the second and third carbon from right to left. An observation: this image and the molecule in the question are not enantiomers.

Why not the others?

B. 2-penthylpropane points out that there is a Penthyl group in the second carbon from left to right or right to left, and that there are 5 core carbons in the structure, instead of six.

C. 4-propylpentane points out that there is a Propyl group in the second carbon from left to right or right to left, and that there are 5 core carbons in the structure, instead of six.

D. Octane ignores the existence of the two methyl groups present on the structure, so it is also the wrong one.

View image peacemonk