Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Let's walk through the steps to find the value of the correlation coefficient \( r \) from the given data.
### Step 1: Calculate the Standard Deviations
To find the correlation coefficient, we first need to calculate the standard deviations of \( x \) and \( y \).
Given:
- Average \( x \) = 60
- Average \( y \) = 95
- Sum of squares of deviations for \( x \) = 920
- Sum of squares of deviations for \( y \) = 1050
- The sum of product of deviations = -545
We assume the sample size \( n \) is such that \( n-1 = 10 \), meaning \( n = 11 \). With \( n-1 \) as our value (which is typically used in the calculation of standard deviation for samples), we compute the standard deviations.
The formula for the standard deviation of \( x \) is:
[tex]\[ \sigma_x = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n-1}} \][/tex]
For \( x \):
[tex]\[ \sigma_x = \sqrt{\frac{920}{10}} \][/tex]
[tex]\[ \sigma_x = \sqrt{92} \][/tex]
[tex]\[ \sigma_x \approx 9.59 \][/tex]
For \( y \):
[tex]\[ \sigma_y = \sqrt{\frac{\sum (y_i - \bar{y})^2}{n-1}} \][/tex]
[tex]\[ \sigma_y = \sqrt{\frac{1050}{10}} \][/tex]
[tex]\[ \sigma_y = \sqrt{105} \][/tex]
[tex]\[ \sigma_y \approx 10.25 \][/tex]
### Step 2: Calculate the Correlation Coefficient \( r \)
The formula for the correlation coefficient \( r \) is:
[tex]\[ r = \frac{\sum((x_i - \bar{x})(y_i - \bar{y}))}{\sqrt{\sum (x_i - \bar{x})^2 \sum (y_i - \bar{y})^2}} \][/tex]
Given the sum of product of deviations:
[tex]\[ \sum ((x_i - \bar{x})(y_i - \bar{y})) = -545 \][/tex]
We use this sum of product of deviations along with the standard deviations calculated above:
[tex]\[ r = \frac{\sum((x_i - \bar{x})(y_i - \bar{y}))}{(n-1) \sigma_x \sigma_y} \][/tex]
Substitute the values:
[tex]\[ r = \frac{-545}{10 \times 9.59 \times 10.25} \][/tex]
Calculate the denominator:
[tex]\[ 9.59 \times 10.25 = 98.2975 \][/tex]
[tex]\[ 10 \times 98.2975 = 982.975 \][/tex]
Now, compute \( r \):
[tex]\[ r = \frac{-545}{982.975} \][/tex]
[tex]\[ r \approx -0.5545 \][/tex]
### Conclusion
Therefore, the correlation coefficient [tex]\( r \approx -0.5545 \)[/tex].
### Step 1: Calculate the Standard Deviations
To find the correlation coefficient, we first need to calculate the standard deviations of \( x \) and \( y \).
Given:
- Average \( x \) = 60
- Average \( y \) = 95
- Sum of squares of deviations for \( x \) = 920
- Sum of squares of deviations for \( y \) = 1050
- The sum of product of deviations = -545
We assume the sample size \( n \) is such that \( n-1 = 10 \), meaning \( n = 11 \). With \( n-1 \) as our value (which is typically used in the calculation of standard deviation for samples), we compute the standard deviations.
The formula for the standard deviation of \( x \) is:
[tex]\[ \sigma_x = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n-1}} \][/tex]
For \( x \):
[tex]\[ \sigma_x = \sqrt{\frac{920}{10}} \][/tex]
[tex]\[ \sigma_x = \sqrt{92} \][/tex]
[tex]\[ \sigma_x \approx 9.59 \][/tex]
For \( y \):
[tex]\[ \sigma_y = \sqrt{\frac{\sum (y_i - \bar{y})^2}{n-1}} \][/tex]
[tex]\[ \sigma_y = \sqrt{\frac{1050}{10}} \][/tex]
[tex]\[ \sigma_y = \sqrt{105} \][/tex]
[tex]\[ \sigma_y \approx 10.25 \][/tex]
### Step 2: Calculate the Correlation Coefficient \( r \)
The formula for the correlation coefficient \( r \) is:
[tex]\[ r = \frac{\sum((x_i - \bar{x})(y_i - \bar{y}))}{\sqrt{\sum (x_i - \bar{x})^2 \sum (y_i - \bar{y})^2}} \][/tex]
Given the sum of product of deviations:
[tex]\[ \sum ((x_i - \bar{x})(y_i - \bar{y})) = -545 \][/tex]
We use this sum of product of deviations along with the standard deviations calculated above:
[tex]\[ r = \frac{\sum((x_i - \bar{x})(y_i - \bar{y}))}{(n-1) \sigma_x \sigma_y} \][/tex]
Substitute the values:
[tex]\[ r = \frac{-545}{10 \times 9.59 \times 10.25} \][/tex]
Calculate the denominator:
[tex]\[ 9.59 \times 10.25 = 98.2975 \][/tex]
[tex]\[ 10 \times 98.2975 = 982.975 \][/tex]
Now, compute \( r \):
[tex]\[ r = \frac{-545}{982.975} \][/tex]
[tex]\[ r \approx -0.5545 \][/tex]
### Conclusion
Therefore, the correlation coefficient [tex]\( r \approx -0.5545 \)[/tex].
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.