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If [tex]x \Rightarrow y[/tex] and [tex]y \Rightarrow z[/tex], which statement must be true?

A. [tex]x \Rightarrow z[/tex]
B. [tex]\neg x \Rightarrow \neg z[/tex]
C. [tex]\neg x \Rightarrow z[/tex]
D. [tex]z \Rightarrow x[/tex]

Sagot :

Let’s analyze the given logical implications step by step:

1. We have the statement \( x \Rightarrow y \). This means if \( x \) is true, then \( y \) must also be true.

2. We also have the statement \( y \Rightarrow z \). This means if \( y \) is true, then \( z \) must also be true.

To determine which statement must be true among the options, let’s utilize the concept of the transitive property of logical implication:

- The transitive property of implication states that if \( x \Rightarrow y \) and \( y \Rightarrow z \), then we can conclude \( x \Rightarrow z \).

Now, let's revisit the options:

A. \( x \Rightarrow z \): From the transitive property of the given implications, we know that if \( x \Rightarrow y \) and \( y \Rightarrow z \), then \( x \Rightarrow z \) must be true. Therefore, this is a correct statement.

B. \( \neg x \Rightarrow \neg z \): This statement does not generally follow from the given implications. It requires additional negation rules and is not supported by the transitive property of implications.

C. \( \neg x \Rightarrow z \): This statement also does not generally follow from the given implications. There is no direct logical connection provided by the given information that leads to this statement.

D. \( z \Rightarrow x \): This statement represents the converse of what we are given which is not implied by the given conditions.

Based on our logical analysis, the correct answer is:
A. [tex]\( x \Rightarrow z \)[/tex].
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