At 200 °C, Kc = 1.40 x 10-10 for the reaction
N,0(g) + NO2(g)
3NO(g)
If 0.123 mol of N20 and 0.453 mol NO2 are placed in a 4.00 L container, what would the NO concentration be if this equilibrium were established?

Question

01-07-2024
Chemistry

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At 200 °C, Kc = 1.40 x 10-10 for the reaction
N,0(g) + NO2(g)
3NO(g)
If 0.123 mol of N20 and 0.453 mol NO2 are placed in a 4.00 L container, what would the NO concentration be if this equilibrium were established?

Sagot :

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At 200 °C, Kc = 1.40 x 10-10 for the reaction N,0(g) + NO2(g) 3NO(g) If 0.123 mol of N20 and 0.453 mol NO2 are placed in a 4.00 L container, what would the NO concentration be if this equilibrium were established?

Sagot :

Other Questions

At 200 °C, Kc = 1.40 x 10-10 for the reaction
N,0(g) + NO2(g)
3NO(g)
If 0.123 mol of N20 and 0.453 mol NO2 are placed in a 4.00 L container, what would the NO concentration be if this equilibrium were established?