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Find the distance between these points:

[tex]\[
\begin{array}{l}
A(5,8), B(-3,4) \\
AB=
\end{array}
\][/tex]

Sagot :

To find the distance between two points \( A(5,8) \) and \( B(-3,4) \) in a Cartesian plane, you can use the distance formula:

[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]

Here, \((x_1, y_1)\) are the coordinates of point \( A \) and \((x_2, y_2)\) are the coordinates of point \( B \).

1. Identify the coordinates of the points:
- Point \( A \) has coordinates \((5, 8)\).
- Point \( B \) has coordinates \((-3, 4)\).

2. Substitute these coordinates into the distance formula:
[tex]\[ d = \sqrt{(-3 - 5)^2 + (4 - 8)^2} \][/tex]

3. Calculate the differences inside the parentheses:
[tex]\[ x_2 - x_1 = -3 - 5 = -8 \][/tex]
[tex]\[ y_2 - y_1 = 4 - 8 = -4 \][/tex]

4. Substitute these differences back into the formula:
[tex]\[ d = \sqrt{(-8)^2 + (-4)^2} \][/tex]

5. Square these differences:
[tex]\[ (-8)^2 = 64 \][/tex]
[tex]\[ (-4)^2 = 16 \][/tex]

6. Add the squared differences:
[tex]\[ 64 + 16 = 80 \][/tex]

7. Finally, take the square root of the sum to find the distance:
[tex]\[ d = \sqrt{80} \][/tex]

8. Simplifying the square root of 80:
[tex]\[ d = \sqrt{16 \times 5} = \sqrt{16} \cdot \sqrt{5} = 4\sqrt{5} \][/tex]

9. Approximating further to a numerical value, we get:
[tex]\[ d \approx 8.94427190999916 \][/tex]

Therefore, the distance between the points [tex]\( A(5,8) \)[/tex] and [tex]\( B(-3,4) \)[/tex] is approximately [tex]\( 8.94427190999916 \)[/tex] units.