Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To prove that in a \( 45^\circ-45^\circ-90^\circ \) triangle the hypotenuse is \(\sqrt{2}\) times the length of each leg, we are given that the triangle is an isosceles right triangle where the legs have equal length \(a\). The proof should proceed by using the Pythagorean theorem and then finding the relationship between the hypotenuse \(c\) and the legs \(a\).
Given:
[tex]\[ a^2 + a^2 = c^2 \][/tex]
Combine like terms on the left side:
[tex]\[ 2a^2 = c^2 \][/tex]
We need to isolate \(c\). For this, we take the principal (positive) square root of both sides of the equation:
[tex]\[ \sqrt{2a^2} = \sqrt{c^2} \][/tex]
Since \(\sqrt{c^2} = c\) and \(\sqrt{2a^2} = \sqrt{2} \cdot \sqrt{a^2} = \sqrt{2} \cdot a\):
[tex]\[ c = \sqrt{2} \cdot a \][/tex]
This final step shows that the length of the hypotenuse \(c\) is \(\sqrt{2}\) times the length of each leg \(a\). Hence, the correct step is to:
Determine the principal square root of both sides of the equation.
Given:
[tex]\[ a^2 + a^2 = c^2 \][/tex]
Combine like terms on the left side:
[tex]\[ 2a^2 = c^2 \][/tex]
We need to isolate \(c\). For this, we take the principal (positive) square root of both sides of the equation:
[tex]\[ \sqrt{2a^2} = \sqrt{c^2} \][/tex]
Since \(\sqrt{c^2} = c\) and \(\sqrt{2a^2} = \sqrt{2} \cdot \sqrt{a^2} = \sqrt{2} \cdot a\):
[tex]\[ c = \sqrt{2} \cdot a \][/tex]
This final step shows that the length of the hypotenuse \(c\) is \(\sqrt{2}\) times the length of each leg \(a\). Hence, the correct step is to:
Determine the principal square root of both sides of the equation.
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.