At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
To prove that in a \( 45^\circ-45^\circ-90^\circ \) triangle the hypotenuse is \(\sqrt{2}\) times the length of each leg, we are given that the triangle is an isosceles right triangle where the legs have equal length \(a\). The proof should proceed by using the Pythagorean theorem and then finding the relationship between the hypotenuse \(c\) and the legs \(a\).
Given:
[tex]\[ a^2 + a^2 = c^2 \][/tex]
Combine like terms on the left side:
[tex]\[ 2a^2 = c^2 \][/tex]
We need to isolate \(c\). For this, we take the principal (positive) square root of both sides of the equation:
[tex]\[ \sqrt{2a^2} = \sqrt{c^2} \][/tex]
Since \(\sqrt{c^2} = c\) and \(\sqrt{2a^2} = \sqrt{2} \cdot \sqrt{a^2} = \sqrt{2} \cdot a\):
[tex]\[ c = \sqrt{2} \cdot a \][/tex]
This final step shows that the length of the hypotenuse \(c\) is \(\sqrt{2}\) times the length of each leg \(a\). Hence, the correct step is to:
Determine the principal square root of both sides of the equation.
Given:
[tex]\[ a^2 + a^2 = c^2 \][/tex]
Combine like terms on the left side:
[tex]\[ 2a^2 = c^2 \][/tex]
We need to isolate \(c\). For this, we take the principal (positive) square root of both sides of the equation:
[tex]\[ \sqrt{2a^2} = \sqrt{c^2} \][/tex]
Since \(\sqrt{c^2} = c\) and \(\sqrt{2a^2} = \sqrt{2} \cdot \sqrt{a^2} = \sqrt{2} \cdot a\):
[tex]\[ c = \sqrt{2} \cdot a \][/tex]
This final step shows that the length of the hypotenuse \(c\) is \(\sqrt{2}\) times the length of each leg \(a\). Hence, the correct step is to:
Determine the principal square root of both sides of the equation.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.