Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To determine which pair of \( P \) and \( a \) will cause the function \( f(x) = P \cdot a^x \) to be an exponential growth function, we need to evaluate the properties of exponential functions.
For a function to be classified as an exponential growth function, the base \( a \) must be greater than 1. An exponential growth function increases as \( x \) increases, and this happens only if \( a > 1 \).
Now, let's evaluate each option:
Option A: \( P = 3 \) and \( a = \frac{1}{4} \)
- Here, the base \( a = \frac{1}{4} \).
- Since \( \frac{1}{4} < 1 \), this function \( f(x) = 3 \cdot (\frac{1}{4})^x \) is not an exponential growth function.
Option B: \( P = 3 \) and \( a = 1 \)
- Here, the base \( a = 1 \).
- Since \( 1 \) is not greater than \( 1 \) (it is equal to 1), the function \( f(x) = 3 \cdot 1^x \) is not an exponential growth function but rather a constant function.
Option C: \( P = \frac{1}{3} \) and \( a = 4 \)
- Here, the base \( a = 4 \).
- Since \( 4 > 1 \), this function \( f(x) = \frac{1}{3} \cdot 4^x \) is an exponential growth function.
Option D: \( P = \frac{1}{3} \) and \( a = \frac{1}{4} \)
- Here, the base \( a = \frac{1}{4} \).
- Since \( \frac{1}{4} < 1 \), this function \( f(x) = \frac{1}{3} \cdot (\frac{1}{4})^x \) is not an exponential growth function.
Therefore, the pair \( P = \frac{1}{3} \) and \( a = 4 \) in Option C is the only one that causes \( f(x) \) to be an exponential growth function.
So, the correct answer is:
C. [tex]\( P = \frac{1}{3} \)[/tex] and [tex]\( a = 4 \)[/tex]
For a function to be classified as an exponential growth function, the base \( a \) must be greater than 1. An exponential growth function increases as \( x \) increases, and this happens only if \( a > 1 \).
Now, let's evaluate each option:
Option A: \( P = 3 \) and \( a = \frac{1}{4} \)
- Here, the base \( a = \frac{1}{4} \).
- Since \( \frac{1}{4} < 1 \), this function \( f(x) = 3 \cdot (\frac{1}{4})^x \) is not an exponential growth function.
Option B: \( P = 3 \) and \( a = 1 \)
- Here, the base \( a = 1 \).
- Since \( 1 \) is not greater than \( 1 \) (it is equal to 1), the function \( f(x) = 3 \cdot 1^x \) is not an exponential growth function but rather a constant function.
Option C: \( P = \frac{1}{3} \) and \( a = 4 \)
- Here, the base \( a = 4 \).
- Since \( 4 > 1 \), this function \( f(x) = \frac{1}{3} \cdot 4^x \) is an exponential growth function.
Option D: \( P = \frac{1}{3} \) and \( a = \frac{1}{4} \)
- Here, the base \( a = \frac{1}{4} \).
- Since \( \frac{1}{4} < 1 \), this function \( f(x) = \frac{1}{3} \cdot (\frac{1}{4})^x \) is not an exponential growth function.
Therefore, the pair \( P = \frac{1}{3} \) and \( a = 4 \) in Option C is the only one that causes \( f(x) \) to be an exponential growth function.
So, the correct answer is:
C. [tex]\( P = \frac{1}{3} \)[/tex] and [tex]\( a = 4 \)[/tex]
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.