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What is the solution set of [tex]\frac{x}{4} \leq \frac{y}{x}[/tex]?

Sagot :

To solve the inequality [tex]\(\frac{x}{4} \leq \frac{y}{x}\)[/tex], let's go through a detailed, step-by-step solution:

1. Rewrite the inequality: Start with the given inequality:
[tex]\[ \frac{x}{4} \leq \frac{y}{x} \][/tex]

2. Multiply both sides by [tex]\(x\)[/tex] (assuming [tex]\(x \neq 0\)[/tex]): Multiplying each side by [tex]\(x\)[/tex] eliminates the denominator on the right side:
[tex]\[ \frac{x \cdot x}{4} \leq y \][/tex]
which simplifies to:
[tex]\[ \frac{x^2}{4} \leq y \][/tex]

3. Isolate [tex]\(y\)[/tex]: To clearly express the solution set, rewrite the inequality to isolate [tex]\(y\)[/tex]:
[tex]\[ y \geq \frac{x^2}{4} \][/tex]

Thus, the solution set for the inequality [tex]\(\frac{x}{4} \leq \frac{y}{x}\)[/tex] is given by:
[tex]\[ y \geq \frac{x^2}{4} \][/tex]

This means that for any value of [tex]\(x\)[/tex], the value of [tex]\(y\)[/tex] must be at least [tex]\(\frac{x^2}{4}\)[/tex] in order to satisfy the inequality.