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What are the solutions to this equation?

[tex]2x^2 = -10x + 12[/tex]

A. [tex]x = -2[/tex]
B. [tex]x = -6[/tex]
C. [tex]x = -3[/tex]
D. [tex]x = 6[/tex]
E. [tex]x = 3[/tex]
F. [tex]x = 1[/tex]

Sagot :

GinnyAnswer
To find the solutions to the quadratic equation [tex]\( 2x^2 + 10x - 12 = 0 \)[/tex], proceed as follows:

1. Write the equation in standard form:
The given equation [tex]\( 2x^2 + 10x - 12 = 0 \)[/tex] is already in standard quadratic form, which is [tex]\( ax^2 + bx + c = 0 \)[/tex], where [tex]\( a = 2 \)[/tex], [tex]\( b = 10 \)[/tex], and [tex]\( c = -12 \)[/tex].

2. Solve the quadratic equation:
By solving the quadratic equation, we find the values of [tex]\( x \)[/tex] that satisfy the equation.

3. Identify the solutions:

From the previous detailed solving steps (not shown here), we know that the solutions to the quadratic equation [tex]\( 2x^2 + 10x - 12 = 0 \)[/tex] are:
[tex]\[ x = -6 \quad \text{and} \quad x = 1 \][/tex]

Therefore, the correct solutions to the equation [tex]\( 2x^2 + 10x - 12 = 0 \)[/tex] are:
- [tex]\( x = -6 \)[/tex]
- [tex]\( x = 1 \)[/tex]

The correct answers to select would be:
- [tex]\( x = -6 \)[/tex]
- [tex]\( x = 1 \)[/tex]
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