At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Answer:
See the below work.
Step-by-step explanation:
To find the outcomes of adding the scores when rolling two dice together, first we make the table of outcomes - refer to the 1st attached picture.
(a)
the total possible scores (outcome) = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}
(b)
The results are not equally likely outcomes since the total numbers of each outcome are unequal:
[tex]\begin{array}{c|c}\cline{1-2}outcome&total\ (frequency)\\\cline{1-2}2&1\\3&2\\4&3\\5&4\\6&5\\7&6\\8&5\\9&4\\10&3\\11&2\\12&1\\\cline{1-2}\Sigma frequencey&36\\\cline{1-2}\end{array}[/tex]
(c)
We can find the probability by using the probability formula:
[tex]\boxed{P(A)=\frac{n(A)}{n(S)} }[/tex]
where:
- [tex]P(A)=\text{probability of event A}[/tex]
- [tex]n(A)=\text{number of outcome of event A}[/tex]
- [tex]n(S) = \text{total number of all outcomes}[/tex]
(i)
Given:
- [tex]n(x=10)=3[/tex]
- [tex]n(S)=36[/tex]
Then:
[tex]\begin{aligned} P(x=10)&=\frac{n(x=10)}{n(S)}\\\\&=\frac{3}{36} \\\\&=\bf\frac{1}{12} \end{aligned}[/tex]
(ii)
Given:
- [tex]n(x=1)=1[/tex]
- [tex]n(S)=36[/tex]
Then:
[tex]\begin{aligned} P(x=1)&=\frac{n(x=1)}{n(S)}\\\\&=\bf\frac{1}{36}\end{aligned}[/tex]
(iii)
Given:
- [tex]n(x=16)=0[/tex]
- [tex]n(S)=36[/tex]
Then:
[tex]\begin{aligned} P(x=16)&=\frac{n(x=16)}{n(S)}\\\\&=\frac{0}{36} \\\\&=\bf0 \end{aligned}[/tex]
(iv)
Given:
- [tex]n(x=12)=1[/tex]
- [tex]n(S)=36[/tex]
Then:
[tex]\begin{aligned} P(x=12)&=\frac{n(x=12)}{n(S)}\\\\&=\bf\frac{1}{36} \end{aligned}[/tex]
(v)
Given:
- [tex]n(x < 6)=1+2+3+4=10[/tex]
- [tex]n(S)=36[/tex]
Then:
[tex]\begin{aligned} P(x < 6)&=\frac{n(x < 6)}{n(S)}\\\\&=\frac{10}{36} \\\\&=\bf\frac{5}{18} \end{aligned}[/tex]

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.