2 C6H14 + 19 O2
→
12 CO2 + 14 H2O

The enthalpy of reaction is −4163.0 kJ/mol. What magnitude of energy (in joules) will be released if 59.92 grams of hexane is burned? (Molar mass of hexane = 86.20 g/mol).

Question

01-07-2024
Chemistry

Answered

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2 C6H14 + 19 O2
→
12 CO2 + 14 H2O

The enthalpy of reaction is −4163.0 kJ/mol. What magnitude of energy (in joules) will be released if 59.92 grams of hexane is burned? (Molar mass of hexane = 86.20 g/mol).

Sagot :

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2 C6H14 + 19 O2 → 12 CO2 + 14 H2O The enthalpy of reaction is −4163.0 kJ/mol. What magnitude of energy (in joules) will be released if 59.92 grams of hexane is burned? (Molar mass of hexane = 86.20 g/mol).

Sagot :

Other Questions

2 C6H14 + 19 O2
→
12 CO2 + 14 H2O

The enthalpy of reaction is −4163.0 kJ/mol. What magnitude of energy (in joules) will be released if 59.92 grams of hexane is burned? (Molar mass of hexane = 86.20 g/mol).