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Sagot :
To determine the probability that Gary chooses a spiral-patterned paper and a green ribbon, we need to follow these steps:
1. Identify the total number of possible combinations:
- There are 4 different patterns of wrapping paper: floral, spiral, cartoon character, and plain.
- There are 3 different ribbon colors: red, blue, and green.
- The total number of combinations is calculated by multiplying the number of patterns by the number of ribbon colors:
[tex]\[ \text{Total combinations} = 4 \text{ patterns} \times 3 \text{ ribbon colors} = 12 \text{ combinations} \][/tex]
2. Identify the number of favorable outcomes:
- We are interested in the specific combination of spiral-patterned paper and a green ribbon.
- There is only one such combination (spiral + green).
3. Calculate the probability:
- The probability of an event is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{1}{12} \][/tex]
Thus, the probability that Gary chooses a spiral-patterned paper and a green ribbon is:
[tex]\(\boxed{\frac{1}{12}}\)[/tex]
So the correct answer is A. [tex]\(\frac{1}{12}\)[/tex].
1. Identify the total number of possible combinations:
- There are 4 different patterns of wrapping paper: floral, spiral, cartoon character, and plain.
- There are 3 different ribbon colors: red, blue, and green.
- The total number of combinations is calculated by multiplying the number of patterns by the number of ribbon colors:
[tex]\[ \text{Total combinations} = 4 \text{ patterns} \times 3 \text{ ribbon colors} = 12 \text{ combinations} \][/tex]
2. Identify the number of favorable outcomes:
- We are interested in the specific combination of spiral-patterned paper and a green ribbon.
- There is only one such combination (spiral + green).
3. Calculate the probability:
- The probability of an event is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{1}{12} \][/tex]
Thus, the probability that Gary chooses a spiral-patterned paper and a green ribbon is:
[tex]\(\boxed{\frac{1}{12}}\)[/tex]
So the correct answer is A. [tex]\(\frac{1}{12}\)[/tex].
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