Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
To determine which of the given chemical equations has a coefficient of 3 in front of any of the reactants when balanced, we need to balance each equation step by step.
1. Equation: [tex]\( \text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \)[/tex]
- Zinc (Zn) appears as 1 atom on each side.
- To balance chlorine (Cl), since there are 2 chlorine atoms in [tex]\( \text{ZnCl}_2 \)[/tex], we need 2 molecules of [tex]\( \text{HCl} \)[/tex]:
[tex]\[ \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \][/tex]
- Now, hydrogen (H) is balanced with 2 hydrogens on both sides.
- This equation is balanced with the coefficients: [tex]\(\text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2\)[/tex]
- Coefficients: 1, 2, 1, 1
- No coefficient of 3 is used for any of the reactants.
2. Equation: [tex]\( \text{H}_2\text{SO}_4 + \text{B(OH)}_3 \rightarrow \text{B}_2(\text{SO}_4)_3 + \text{H}_2\text{O} \)[/tex]
- Sulfur (S) and Oxygen (O) in [tex]\( \text{H}_2\text{SO}_4 \)[/tex] and [tex]\( \text{B}_2(\text{SO}_4)_3 \)[/tex].
- Boron (B) appears as 2 atoms on the product side:
[tex]\[ \text{H}_2\text{SO}_4 + 2\text{B(OH)}_3 \rightarrow \text{B}_2(\text{SO}_4)_3 + \text{H}_2\text{O} \][/tex]
- Now, balance hydrogens and oxygens:
[tex]\[ \text{H}_2\text{SO}_4 + 6\text{H}_2\text{O} \rightarrow 2\text{B}_2(\text{SO}_4)_3 + 6\text{H}_2\text{O} \][/tex]
- Coefficients: 1, 2, 1, 6
- No coefficient of 3 is used for any of the reactants.
3. Equation: [tex]\( \text{Fe} + \text{AgNO}_3 \rightarrow \text{Fe(NO}_3)_2 + \text{Ag} \)[/tex]
- Iron (Fe): 1 Fe on the left and right.
- Silver (Ag): To balance Ag, we need 2 Ag on the product side:
[tex]\[ 3\text{Fe} + 2\text{AgNO}_3 \rightarrow \text{Fe(NO}_3)_2 + 2\text{Ag} \][/tex]
- Coefficients: 3, 2, 1, 2
- A coefficient of 3 is used in front of Fe.
4. Equation: \( C_2H_4O_2 + O_2 \rightarrow CO_2 + H_2O
- Balance oxygens (O):
- To balance CO2 (and H2O balance as 2):
[tex]\[ \text{C}_2\text{H}_4\text{O}_2 + 2\text{O}_2 \rightarrow 2\text{CO}_2 + 2\text{H}_2\text{O} \][/tex]
- Coefficients: 1, 2, 2, 2
- No coefficient of 3 is used for any of the reactants.
After evaluating each equation, we find that the only equation balanced to have a coefficient of 3 in front of one of the reactants is:
[tex]\[ 3\text{Fe} + 2\text{AgNO}_3 \rightarrow \text{Fe(NO}_3)_2 + 2\text{Ag} \][/tex]
So, the answer is:
[tex]\[ \boxed{3} \][/tex]
1. Equation: [tex]\( \text{Zn} + \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \)[/tex]
- Zinc (Zn) appears as 1 atom on each side.
- To balance chlorine (Cl), since there are 2 chlorine atoms in [tex]\( \text{ZnCl}_2 \)[/tex], we need 2 molecules of [tex]\( \text{HCl} \)[/tex]:
[tex]\[ \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \][/tex]
- Now, hydrogen (H) is balanced with 2 hydrogens on both sides.
- This equation is balanced with the coefficients: [tex]\(\text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2\)[/tex]
- Coefficients: 1, 2, 1, 1
- No coefficient of 3 is used for any of the reactants.
2. Equation: [tex]\( \text{H}_2\text{SO}_4 + \text{B(OH)}_3 \rightarrow \text{B}_2(\text{SO}_4)_3 + \text{H}_2\text{O} \)[/tex]
- Sulfur (S) and Oxygen (O) in [tex]\( \text{H}_2\text{SO}_4 \)[/tex] and [tex]\( \text{B}_2(\text{SO}_4)_3 \)[/tex].
- Boron (B) appears as 2 atoms on the product side:
[tex]\[ \text{H}_2\text{SO}_4 + 2\text{B(OH)}_3 \rightarrow \text{B}_2(\text{SO}_4)_3 + \text{H}_2\text{O} \][/tex]
- Now, balance hydrogens and oxygens:
[tex]\[ \text{H}_2\text{SO}_4 + 6\text{H}_2\text{O} \rightarrow 2\text{B}_2(\text{SO}_4)_3 + 6\text{H}_2\text{O} \][/tex]
- Coefficients: 1, 2, 1, 6
- No coefficient of 3 is used for any of the reactants.
3. Equation: [tex]\( \text{Fe} + \text{AgNO}_3 \rightarrow \text{Fe(NO}_3)_2 + \text{Ag} \)[/tex]
- Iron (Fe): 1 Fe on the left and right.
- Silver (Ag): To balance Ag, we need 2 Ag on the product side:
[tex]\[ 3\text{Fe} + 2\text{AgNO}_3 \rightarrow \text{Fe(NO}_3)_2 + 2\text{Ag} \][/tex]
- Coefficients: 3, 2, 1, 2
- A coefficient of 3 is used in front of Fe.
4. Equation: \( C_2H_4O_2 + O_2 \rightarrow CO_2 + H_2O
- Balance oxygens (O):
- To balance CO2 (and H2O balance as 2):
[tex]\[ \text{C}_2\text{H}_4\text{O}_2 + 2\text{O}_2 \rightarrow 2\text{CO}_2 + 2\text{H}_2\text{O} \][/tex]
- Coefficients: 1, 2, 2, 2
- No coefficient of 3 is used for any of the reactants.
After evaluating each equation, we find that the only equation balanced to have a coefficient of 3 in front of one of the reactants is:
[tex]\[ 3\text{Fe} + 2\text{AgNO}_3 \rightarrow \text{Fe(NO}_3)_2 + 2\text{Ag} \][/tex]
So, the answer is:
[tex]\[ \boxed{3} \][/tex]
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
