To solve for the antiderivative [tex]\( F(x) \)[/tex] of the function [tex]\( f(x) = x^5 - 4x^{-2} - 5 \)[/tex] that satisfies the condition [tex]\( F(1) = 1 \)[/tex], let's go through the steps systematically.
### Step 1: Find the Indefinite Integral
First, we need to find the indefinite integral (antiderivative) of [tex]\( f(x) \)[/tex].
[tex]\[
F(x) = \int (x^5 - 4x^{-2} - 5) \, dx
\][/tex]
We can integrate the function term by term:
1. [tex]\(\int x^5 \, dx = \frac{x^6}{6}\)[/tex]
2. [tex]\(\int -4x^{-2} \, dx = -4 \cdot \int x^{-2} \, dx = -4 \cdot \left( -\frac{1}{x} \right) = \frac{4}{x}\)[/tex]
3. [tex]\(\int -5 \, dx = -5x\)[/tex]
So, combining these results, we get:
[tex]\[
F(x) = \frac{x^6}{6} + \frac{4}{x} - 5x + C
\][/tex]
Where [tex]\( C \)[/tex] is the constant of integration.
### Step 2: Solve for the Constant [tex]\( C \)[/tex]
We are given the condition [tex]\( F(1) = 1 \)[/tex]. We use this condition to solve for [tex]\( C \)[/tex].
[tex]\[
F(1) = \frac{1^6}{6} + \frac{4}{1} - 5 \cdot 1 + C = 1
\][/tex]
Simplifying this equation:
[tex]\[
\frac{1}{6} + 4 - 5 + C = 1
\][/tex]
[tex]\[
\frac{1}{6} - 1 + C = 1
\][/tex]
[tex]\[
C - \frac{5}{6} = 1
\][/tex]
[tex]\[
C = 1 + \frac{5}{6}
\][/tex]
[tex]\[
C = \frac{6}{6} + \frac{5}{6}
\][/tex]
[tex]\[
C = \frac{11}{6}
\][/tex]
### Step 3: Write the Final Antiderivative
Substitute [tex]\( C = \frac{11}{6} \)[/tex] back into the antiderivative:
[tex]\[
F(x) = \frac{x^6}{6} + \frac{4}{x} - 5x + \frac{11}{6}
\][/tex]
So the antiderivative [tex]\( F(x) \)[/tex] that satisfies [tex]\( F(1) = 1 \)[/tex] is:
[tex]\[
F(x) = \frac{x^6}{6} + \frac{4}{x} - 5x + \frac{11}{6}
\][/tex]
Thus, the final answer is:
[tex]\[
F(x) = \boxed{\frac{x^6}{6} + \frac{4}{x} - 5x + \frac{11}{6}}
\][/tex]
