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Find the perimeter and area of a rectangle with a length of 12 feet and a width of 3 feet.

A. Perimeter:
B. Area:


Sagot :

To solve this problem, we need to find the perimeter and the area of a rectangle with the given dimensions: a length of 12 feet and a width of 3 feet.

### Step-by-Step Solution:

#### Perimeter of the Rectangle

1. Formula for the perimeter:
The perimeter [tex]\( P \)[/tex] of a rectangle is calculated using the formula:
[tex]\[ P = 2 \times (\text{length} + \text{width}) \][/tex]

2. Substitute the given values:
Here, the length ([tex]\( l \)[/tex]) is 12 feet and the width ([tex]\( w \)[/tex]) is 3 feet. Substitute these values into the formula:
[tex]\[ P = 2 \times (12 + 3) \][/tex]

3. Simplify the expression:
First, add the length and width:
[tex]\[ 12 + 3 = 15 \][/tex]
Then, multiply by 2:
[tex]\[ 2 \times 15 = 30 \][/tex]

4. Result for the perimeter:
[tex]\[ P = 30 \text{ feet} \][/tex]

#### Area of the Rectangle

1. Formula for the area:
The area [tex]\( A \)[/tex] of a rectangle is calculated using the formula:
[tex]\[ A = \text{length} \times \text{width} \][/tex]

2. Substitute the given values:
Using the length ([tex]\( l \)[/tex]) of 12 feet and the width ([tex]\( w \)[/tex]) of 3 feet, the formula becomes:
[tex]\[ A = 12 \times 3 \][/tex]

3. Simplify the expression:
[tex]\[ 12 \times 3 = 36 \][/tex]

4. Result for the area:
[tex]\[ A = 36 \text{ square feet} \][/tex]

### Final Answer:

- The perimeter of the rectangle is 30 feet.
- The area of the rectangle is 36 square feet.