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(g) Define Scanner and write one of its uses.

(h) If a body starts from rest and attains a velocity of [tex]20 \, \text{m/s}[/tex], what distance does it cover in 1 minute?

Sagot :

Certainly! Let's address each part of this question in turn.

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### (g) Define Scanner and write its any one use.

Definition:
A Scanner is an input device used in computing to convert physical documents and images into digital format. Scanners use light to capture the image or text on a document and then convert it into a digital file that can be stored, edited, or shared electronically.

One Use:
One common use of a scanner is to digitize paper documents for archiving. This allows organizations and individuals to keep records in a digital format, which saves space and makes it easier to organize and access important documents.

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### (h) If a body starts from rest and attains a velocity of 20 m/s, calculate the distance covered in 1 minute.

To find the distance covered by the body, we can use the kinematic equation for uniformly accelerated motion, given that the body starts from rest. Here's a step-by-step explanation:

1. Given Data:
- Initial Velocity ([tex]\( u \)[/tex]): 0 m/s (since the body starts from rest)
- Final Velocity ([tex]\( v \)[/tex]): 20 m/s
- Time ([tex]\( t \)[/tex]): 1 minute = 60 seconds

2. Formula Used:
The distance covered ([tex]\( s \)[/tex]) when initial velocity and final velocity are known can be calculated using the formula for average velocity.

The average velocity of a body undergoing uniform acceleration is given by:
[tex]\[ \text{Average Velocity} = \frac{u + v}{2} \][/tex]

The distance covered can then be found by multiplying the average velocity by the time:
[tex]\[ s = \text{Average Velocity} \times t \][/tex]
Substituting the average velocity formula into the distance formula, we get:
[tex]\[ s = \frac{u + v}{2} \times t \][/tex]

3. Substitute the Given Values:
[tex]\[ s = \frac{0 \, \text{m/s} + 20 \, \text{m/s}}{2} \times 60 \, \text{s} \][/tex]

4. Calculate the Distance:
[tex]\[ s = \frac{20 \, \text{m/s}}{2} \times 60 \, \text{s} \][/tex]
[tex]\[ s = 10 \, \text{m/s} \times 60 \, \text{s} \][/tex]
[tex]\[ s = 600 \, \text{meters} \][/tex]

Therefore, the body covers a distance of 600 meters in 1 minute.

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