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The sides of an equilateral triangle are 8 units long. What is the length of the altitude of the triangle?

A. [tex]\( 5 \sqrt{2} \)[/tex] units
B. [tex]\( 4 \sqrt{3} \)[/tex] units
C. [tex]\( 10 \sqrt{2} \)[/tex] units
D. [tex]\( 16 \sqrt{5} \)[/tex] units


Sagot :

To determine the altitude of an equilateral triangle with sides of length 8 units, we can use properties of equilateral triangles.

1. Identify the formula for the altitude of an equilateral triangle:

The altitude (height) [tex]\( h \)[/tex] of an equilateral triangle can be calculated using the formula:
[tex]\[ h = \frac{\sqrt{3}}{2} \times \text{side length} \][/tex]

2. Substitute the side length into the formula:

Given that the side length is 8 units, we substitute this value into the formula:
[tex]\[ h = \frac{\sqrt{3}}{2} \times 8 \][/tex]

3. Simplify the expression:
[tex]\[ h = \frac{\sqrt{3} \times 8}{2} \][/tex]
[tex]\[ h = \frac{8\sqrt{3}}{2} \][/tex]
[tex]\[ h = 4\sqrt{3} \][/tex]

Therefore, the altitude of the equilateral triangle with side lengths of 8 units is [tex]\( 4\sqrt{3} \)[/tex] units.

Among the given options:
- [tex]\( 5\sqrt{2} \)[/tex] units
- [tex]\( 4\sqrt{3} \)[/tex] units
- [tex]\( 10\sqrt{2} \)[/tex] units
- [tex]\( 16\sqrt{5} \)[/tex] units

The correct answer is [tex]\( 4\sqrt{3} \)[/tex] units.