Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To solve the quadratic equation [tex]\(2x^2 + 2x = 9\)[/tex], we first need to rewrite it in standard form [tex]\(ax^2 + bx + c = 0\)[/tex].
Starting from:
[tex]\[ 2x^2 + 2x = 9 \][/tex]
Subtract 9 from both sides to obtain:
[tex]\[ 2x^2 + 2x - 9 = 0 \][/tex]
Here, the coefficients are [tex]\(a = 2\)[/tex], [tex]\(b = 2\)[/tex], and [tex]\(c = -9\)[/tex].
We will use the quadratic formula:
[tex]\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \][/tex]
First, calculate the discriminant, [tex]\(\Delta\)[/tex]:
[tex]\[ \Delta = b^2 - 4ac \][/tex]
[tex]\[ \Delta = 2^2 - 4(2)(-9) \][/tex]
[tex]\[ \Delta = 4 + 72 \][/tex]
[tex]\[ \Delta = 76 \][/tex]
Since the discriminant is positive, we will have two distinct real roots.
Next, we find the two solutions using the quadratic formula:
For [tex]\( x_1 \)[/tex]:
[tex]\[ x_1 = \frac{-b + \sqrt{\Delta}}{2a} \][/tex]
[tex]\[ x_1 = \frac{-2 + \sqrt{76}}{2(2)} \][/tex]
[tex]\[ x_1 = \frac{-2 + \sqrt{76}}{4} \][/tex]
[tex]\[ x_1 \approx \frac{-2 + 8.72}{4} \][/tex]
[tex]\[ x_1 \approx \frac{6.72}{4} \][/tex]
[tex]\[ x_1 \approx 1.68 \][/tex]
For [tex]\( x_2 \)[/tex]:
[tex]\[ x_2 = \frac{-b - \sqrt{\Delta}}{2a} \][/tex]
[tex]\[ x_2 = \frac{-2 - \sqrt{76}}{2(2)} \][/tex]
[tex]\[ x_2 = \frac{-2 - 8.72}{4} \][/tex]
[tex]\[ x_2 \approx \frac{-10.72}{4} \][/tex]
[tex]\[ x_2 \approx -2.68 \][/tex]
Thus, the solutions to the quadratic equation [tex]\(2x^2 + 2x - 9 = 0\)[/tex] are:
[tex]\[ x \approx 1.68, -2.68 \][/tex]
These results are rounded to the nearest hundredth.
Starting from:
[tex]\[ 2x^2 + 2x = 9 \][/tex]
Subtract 9 from both sides to obtain:
[tex]\[ 2x^2 + 2x - 9 = 0 \][/tex]
Here, the coefficients are [tex]\(a = 2\)[/tex], [tex]\(b = 2\)[/tex], and [tex]\(c = -9\)[/tex].
We will use the quadratic formula:
[tex]\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \][/tex]
First, calculate the discriminant, [tex]\(\Delta\)[/tex]:
[tex]\[ \Delta = b^2 - 4ac \][/tex]
[tex]\[ \Delta = 2^2 - 4(2)(-9) \][/tex]
[tex]\[ \Delta = 4 + 72 \][/tex]
[tex]\[ \Delta = 76 \][/tex]
Since the discriminant is positive, we will have two distinct real roots.
Next, we find the two solutions using the quadratic formula:
For [tex]\( x_1 \)[/tex]:
[tex]\[ x_1 = \frac{-b + \sqrt{\Delta}}{2a} \][/tex]
[tex]\[ x_1 = \frac{-2 + \sqrt{76}}{2(2)} \][/tex]
[tex]\[ x_1 = \frac{-2 + \sqrt{76}}{4} \][/tex]
[tex]\[ x_1 \approx \frac{-2 + 8.72}{4} \][/tex]
[tex]\[ x_1 \approx \frac{6.72}{4} \][/tex]
[tex]\[ x_1 \approx 1.68 \][/tex]
For [tex]\( x_2 \)[/tex]:
[tex]\[ x_2 = \frac{-b - \sqrt{\Delta}}{2a} \][/tex]
[tex]\[ x_2 = \frac{-2 - \sqrt{76}}{2(2)} \][/tex]
[tex]\[ x_2 = \frac{-2 - 8.72}{4} \][/tex]
[tex]\[ x_2 \approx \frac{-10.72}{4} \][/tex]
[tex]\[ x_2 \approx -2.68 \][/tex]
Thus, the solutions to the quadratic equation [tex]\(2x^2 + 2x - 9 = 0\)[/tex] are:
[tex]\[ x \approx 1.68, -2.68 \][/tex]
These results are rounded to the nearest hundredth.
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.